It looks like this is a square pyramid net, and to find the surface area you need to know the base and height. By looking at the image 5 ft is the height and the base is 3 ft.
The surface area of the square pyramid is <u>40.32</u>
hope this helps!
It should be -3 I hope this helps
Use b for bicycles b and t for tricycles.
We know that each bicycle has 2 wheels, and each tricycle has 3 wheels, and if the entire number of wheels is 57, that means the
equation would be: 2b + 3t = 57
We can "separate" b by calling it "25 - t" as an alternative,
2(25 - t) + 3t = 57, or
50 - 2t + 3t = 57,
or 50 + t = 57, so
t = 7 So there must be 18 bicycles and 7 tricycles.
CHECKING:You can check this out by multiplying 7 tricycles x 3 wheels, which is 21,
and 18 bicycles x 2 wheels, which is 36
36 + 21 = 57
<span>N(t) = 16t ; Distance north of spot at time t for the liner.
W(t) = 14(t-1); Distance west of spot at time t for the tanker.
d(t) = sqrt(N(t)^2 + W(t)^2) ; Distance between both ships at time t.
Let's create a function to express the distance north of the spot that the luxury liner is at time t. We will use the value t as representing "the number of hours since 2 p.m." Since the liner was there at exactly 2 p.m. and is traveling 16 kph, the function is
N(t) = 16t
Now let's create the same function for how far west the tanker is from the spot. Since the tanker was there at 3 p.m. (t = 1 by the definition above), the function is slightly more complicated, and is
W(t) = 14(t-1)
The distance between the 2 ships is easy. Just use the pythagorean theorem. So
d(t) = sqrt(N(t)^2 + W(t)^2)
If you want the function for d() to be expanded, just substitute the other functions, so
d(t) = sqrt((16t)^2 + (14(t-1))^2)
d(t) = sqrt(256t^2 + (14t-14)^2)
d(t) = sqrt(256t^2 + (196t^2 - 392t + 196) )
d(t) = sqrt(452t^2 - 392t + 196)</span>
