Volume = area of base *height
20 = pir^2 *h
20 = 3,14*4*h
h = 20/12,56 = 1,59 rounded 1,6
- using the triangle formed by radius,the height of cup and the slant height of cup so we can writing that
tan ß = h/r so tan ß = 1,6/2 = 0,8
tan ß = 0,8 so ß = arctan 0,8 = 38,6 degrees so 39 degrees
hope helped
Answer: D it the For the way they have as examples
what do you need help on. what the problem
Slope point form :
To put in slope point form, label any of the points as either X1,y1 and X and y, then plug in those values into the following equation form.
Y - y1 = m(X-X1)
But before, we must solve for the m value or slope.
M = y2-y1/x2-X1
M = 5/2 - -1/2 / -1/2 - 3/2.
M = 5/2 + 1/2 / -(1/2+3/2)
M = 6/2 / -(4/2)
M = 3/-2
Now we can place it in slope point and also in standard form of a line.
Y-y1 = m(X -X1)
Y - -1/2 = -3/2(X - 3/2)
Y + 1/2 = -3/2(X - 3/2)
This is in slope point form.
Y + 1/2 = -3/2x + 9/4
Y + 1/2 - 1/2 = -3/2x + 9/4 - 1/2
1/2 = 2/4
Y = -3/2x + 7/4
-3/2x = -6/4x
Y = -6/4x + 7/4
Y • 4 = 4( -6/4 X + 7/4)
4y = -6x + 7
4y + 6x = -6x + 6x +7
6x + 4y = 7
This is in standard form. If you have any questions of the steps just ask.
I hope this helps you
1)
x= -2y
2. (-2y)+4y=0
0=0
2)
x+2x= -3
x=-1
y= -2
3)
7x+2x+2=4
9x=2
x=2/9
y=2/9+1
y=11/9
206 X .4 = 82.4
That's the answer.
