Factorize using the difference of squares identity.
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Step-by-step explanation:
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Answer:
The number of times members and non-members will have to rent a boat in order to pay the same amount=20
Step-by-step explanation:
We can have two expressions to show the total cost paid by a member and non-member;
Total cost by member=Cost per summer season+cost per number of times they rent a boat×number of times they rent a boat
where;
Cost per summer season=$105
Cost per number of times they rent a boat=$9.50
Number of times they rent a boat=n
Replacing;
Total cost by a member=105+(9.5×n)=9.5 n+105......equation 1
Total cost by a non-member=Cost per number of times they rent a boat×number of times they rent a boat
where;
Cost per number of times they rent a boat=$14.75
Number of times they rent a boat=n
Replacing;
Total cost by a non-member=(14.75×n)=14.75 n......equation 2
To calculate the number of times they would have to rent a boat in order to pay the same amount, we equate equation 1 to equation 2
9.5 n+105=14.75 n
14.75 n-9.5 n=105
5.25 n=105
n=105/5.25
n=20
The number of times members and non-members will have to rent a boat in order to pay the same amount=20
The answer is "quadrant II" because first u go five left because of the negative five which is on the x axis then go up 10 because of the positive 10 which on the y axis
