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Crank
2 years ago
12

Find the area of a circle with diameter 12 cm.

Mathematics
1 answer:
Anastasy [175]2 years ago
8 0

Answer:

113.1cm²

Step-by-step explanation:

I believe this is the answer if not I'm so sorry for getting it wrong.

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If a1=6 and an=2an-1 then find the value of a4
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The absolute value be pie or square because Pio screwed because the circumference is alsoHope this helps
5 0
2 years ago
Given f(x) = 4(x - 8), determine the value of f(10).
Ilya [14]

Answer:

f(10) = 8

Step-by-step explanation:

f(x) = 4(x - 8)

Let x = 10

f(10) = 4 ( 10-8)

       = 4 ( 2)

      = 8

8 0
2 years ago
Read 2 more answers
7/2 ≥ b + 9/5. and btw, the ones that has the slashes are fractions. :3
Ainat [17]

Answer:

I believe it's

* B. b<1 7/10

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6 0
2 years ago
QUESTION 1
Kitty [74]

It's difficult to make out what the force and displacement vectors are supposed to be, so I'll generalize.

Let <em>θ</em> be the angle between the force vector <em>F</em> and the displacement vector <em>r</em>. The work <em>W</em> done by <em>F</em> in the direction of <em>r</em> is

<em>W</em> = <em>F</em> • <em>r</em> cos(<em>θ</em>)

The cosine of the angle between the vectors can be obtained from the dot product identity,

<em>a</em> • <em>b</em> = ||<em>a</em>|| ||<em>b</em>|| cos(<em>θ</em>)   ==>   cos(<em>θ</em>) = (<em>a</em> • <em>b</em>) / (||<em>a</em>|| ||<em>b</em>||)

so that

<em>W</em> = (<em>F</em> • <em>r</em>)² / (||<em>F</em>|| ||<em>r</em>||)

For instance, if <em>F</em> = 3<em>i</em> + <em>j</em> + <em>k</em> and <em>r</em> = 7<em>i</em> - 7<em>j</em> - <em>k</em> (which is my closest guess to the given vectors' components), then the work done by <em>F</em> along <em>r</em> is

<em>W</em> = ((3<em>i</em> + <em>j</em> + <em>k</em>) • (7<em>i</em> - 7<em>j</em> - <em>k</em>))² / (√(3² + 1² + 1²) √(7² + (-7)² + (-1)²))

==>   <em>W</em> ≈ 5.12 J

(assuming <em>F</em> and <em>r</em> are measured in Newtons (N) and meters (m), respectively).

3 0
3 years ago
6.4 in is what is cm
yarga [219]
It is 16.256 because I went to google and found it.... yep that simple.
5 0
3 years ago
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