Answer:
The required specific heat is 196.94 joule per kg per °C
Step-by-step explanation:
Given as :
The heat generated = Q = 85.87 J
Mass of substance (m)= 34.8 gram = 0.0348 kg
Change in temperature = T2 - T1 = 34.29°C - 21.76°C = 12.53°C
Let the specific heat = S
Now we know that
Heat = Mass × specific heat × change in temperature
Or, Q = msΔt
Or, 85.87 = (0.0348 kg ) × S × 12.53°C
Or , 85.87 = 0.4360 × S
Or, S = 
∴ S = 196.94 joule per kg per °C
Hence the required specific heat is 196.94 joule per kg per °C Answer
First we must change these numbers to improper fractions:


So then we set it up:
÷ 
When we divide fractions like this, we must flip the second fraction and change the sign from division to multiplication like so:

Then we solve:

Then if we divide the numerator and the denominator by 9, we get:
or, in mixed-number form,
.
2 < x < 5
i think this is the answer
Answer:
Se llama un reemplazo
Step-by-step explanation: