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katrin [286]
3 years ago
6

Joan receives a $7 weekly allowance plus $6 for each hour she helps her father paint. Ernie writes the equa on to represent the

rela onship between the number of hours he helps his father with yard work and his weekly allowance. Which statement best describes the graphs of their earnings for one week?
A) The lines have the same slope.

B) The lines are both proporonal.

C) The lines have the same x ‐intercept.

D) The lines have the same y ‐intercept.
Mathematics
2 answers:
zalisa [80]3 years ago
7 0
C... hope this will help!
Bond [772]3 years ago
3 0
Make an equation for each and then graph! It should be easy from there.
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Adding Mixed Numbers<br> Find each sum. Simplify your answer.<br> 1. 5+31 =
tigry1 [53]

Answer:

36:)

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
. Find their present ages. 6 years ago a man's age was six times the age of his son. 4 years hence, thrice his age will be equal
ddd [48]

<u>The present age of the man is 36 years and his son is 11 years.</u>

Answer:

Solution given:

let the age of man be x.

and his son be y.

By question

x-6=6(y-6)

x=6y-36+6

x=6y-30. ......(1)

and

3(x+4)=8(y+4)

3x+12=8y+32

3x=8y+32-12

3x=8y+20. ...(2)

substituting value of x in equation 2 ,we get

3(6y-30)=8y+20

18y-90=8y+20

18y-8y=90+20

10y=110

y=110/10

y=11 years

again substituting value of y in equation 1 we get

x=6*11-30

x=66-30

x=36 years

5 0
1 year ago
A student deposits the same amount of money into her bank account each week. At the end of the second week she has $30 in her ac
Nonamiya [84]
The student will have $135 in her bank account at the end of the ninth week. You can fine this out by finding out the amount she deposits a week and to do this you would take the $30 and divide it by 2 because she had $30 at the end of the second week. 
30/2=15
So you see that the student deposits $15 each week, so to find out how much money she will have in 9 weeks you will multiply her $15 by 9.
15x9=135
So the student will have $135 at the end of the ninth week. 
6 0
2 years ago
Rita makes and sells necklaces. The materials to make each necklace cost $2.75. Last week she made 8 necklaces and wants to make
Tresset [83]

Answer:

The error she made was that she was adding x and 2.75. She should subtract 2.75 from x.

Another mistake that she made was that she sold each for $7 assuming that she would make a profit of 78, but she should see each necklace for $12.5 so that she could make a profit of $78.

Step-by-step explanation:

The error she made was that she was adding x and 2.75.

She should write the equation as 8 (x - 2.75) = 78; as she spends $2.75 to make a necklace.

By using the correct equation: 8 (x - 2.75) = 78

=> 8x - 22 = 78

=> 8x = 78 + 22

=> 8x = 100

=> x = 100/8

=> x = 12.5

Another mistake that she made was that she sold each for $7 assuming that she would make a profit of 78, but she should see each necklace for $12.5 so that she could make a profit of $78.

Hope this helps you.

3 0
3 years ago
Consider the function g(x) = 10/x
ss7ja [257]
<span><span>The correct answers are:
</span><span>(1) The vertical asymptote is x = 0
(2) The horizontal asymptote is y = 0

</span><span>Explanation:
</span><span>(1) To find the vertical asymptote, put the denominator of the rational function equals to zero.

Rational Function = g(x) = </span></span>\frac{10}{x}<span>

Denominator = x = 0

Hence the vertical asymptote is x = 0.

(2) To find the horizontal asymptote, check the power of x in numerator against the power of x in denominator as follows:

Given function = g(x) = </span>\frac{10}{x}<span>

We can write it as:

g(x) = </span>\frac{10 * x^0}{x^1}<span>

If power of x in numerator is less than the power of x in denomenator, then the horizontal asymptote will be y=0.
If power of x in numerator is equal to the power of x in denomenator, then the horizontal asymptote will be y=(co-efficient in numerator)/(co-efficient in denomenator).
If power of x in numerator is greater than the power of x in denomenator, then there will be no horizontal asymptote.

In above case, 0 < 1, therefore, the horizontal asymptote is y = 0
</span>
5 0
3 years ago
Read 2 more answers
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