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snow_lady [41]
3 years ago
5

He normal pulse rate of a 13-year-old is between 70 and 100 beats per minute. As part of a health program, the medical staff at

Grant Middle School measured the resting pulse rate of 12 randomly selected students in grades 7 and 8. The box plot shows the data for each group. Which statement correctly compares the data sets?
The difference of the medians is about half of the interquartile range of either data set.
The difference of the medians is about 2 times the interquartile range of either data set.
The difference of the medians is about one-fourth of the interquartile range of either data set.
The difference of the medians is about 4 times the interquartile range of either data set.

Mathematics
2 answers:
GaryK [48]3 years ago
7 0
T<span>he difference of the medians is about half of the interquartile range of either data set.</span>
SVEN [57.7K]3 years ago
6 0
From the box plot, it can be seen that for grade 7 students,
The least value is 72 and the highest value is 91. The lower and the upper quartiles are 78 and 88 respectively while the median is 84.

Thus, interquatile range of <span>the resting pulse rate of grade 7 students is upper quatile - lower quartle = 88 - 78 = 10

</span>Similarly, from the box plot, it can be seen that for grade 8 students,
The least value is 76 and the highest value is 97. The lower and the upper quartiles are 85 and 94 respectively while the median is 89.

Thus, interquatile range of the resting pulse rate of grade 8 students is upper quatile - lower quartle = 94 - 85 = 9

The difference of the medians <span>of the resting pulse rate of grade 7 students and grade 8 students is 89 - 84 = 5

Therefore, t</span><span>he difference of the medians is about half of the interquartile range of either data set.</span>
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Share $600 between Anna and Raman in the ratio 3:7 and 1:4
Ulleksa [173]

Answer:

3 : 7 =>

Anna = $180

Raman = $420

1 : 4 =>

Anna = $120

Raman = $480

Step-by-step explanation:

<u>Shares when ratio is 3 : 7</u>

Anna : Raman = 3 : 7

Sum of ratio 10

Anna's share=

                   \frac{3}{10} \times 600 = \$  180

Raman 's share=

                  \frac{7}{10} \times 600 = \$ 420

<u>Shares when ratio is 1 : 4</u>

Anna : Raman = 1 : 4

Sum of ratio = 5

Anna 's share =

                   \frac{1}{5} \times 600 = \$ 120

Raman's share =

                  \frac{4}{5} \times 600 = \$ 480

8 0
3 years ago
An ethanol railroad tariff is a fee charge for shipments of ethanol on public railroads. The Agriculture Marketing Service publi
Stels [109]

Answer:

The appropriate response is "0.9476".

Step-by-step explanation:

The given values are:

Standard deviation,

\sigma=1150

Randomly selected railroad-car shipments,

n = 500

As we know,

⇒ \sigma \bar{x}=\frac{\sigma}{\sqrt{n} }

On substituting the values, we get

⇒      =\frac{1150}{\sqrt{500} }

then,

⇒      =P(-1.94

⇒      =P(Z

On using the table of P, we get

⇒      =0.9738 - 0.0262

⇒      =0.9476

3 0
3 years ago
PLEASE HELP ME!!!!!!!!!!!!!!!
Vinil7 [7]

Answer:

The last one

Step-by-step explanation:

4 0
4 years ago
When she adds 2 to both sides, the equation 4x = 3x results. Which solution will best illustrate what happens to x ?
Natasha2012 [34]

Step-by-step explanation:

4x=3x

2+4x=3x+2

4x-3x=2-2

1x=0

x=1/0

X=0

(i think the question given was incomplete but this waht i could do with the given statement)

4 0
3 years ago
Read 2 more answers
A polynomial function has a zero at 4 (multiplicity 3) and 0 (multiplicity 1). Write a function in standard form that can repres
VLD [36.1K]

Answer:

(x^4) - 64x

Step-by-step explanation:

zeros at 4 and 0 are the roots so can be factor as x*(x-4) and the multiplicity tels to what power you have to raise those factors

x^{1} *(x-4)^{3} becuase multiplicity of 1 for root at 0, and multiplicity of 3 at root 4

now to write this in standard form

x*(x-4)^{3} = \\x*(x-4)(x^{2} +4x+16)= \\(x^{2} -4x)(x^{2} +4x+16) = \\x^{4} +4x^{3} +16x^{2} -4x^{3} -16x^{2} -64x = \\x^{4} -64x

8 0
3 years ago
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