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tatuchka [14]
3 years ago
5

What's is the missing number in this pattern.2, 5, 7, 12 ,19, 31, , ​

Mathematics
1 answer:
Ierofanga [76]3 years ago
6 0

Answer:

50

Step-by-step explanation:

2 + 3 = 5

<u>5</u> + 2 = 7

<em>7</em> + <u>5</u> = 12

12 + <em>7</em> = 19

<u>19</u> + 12 = 31

31+ <u>19</u> = 50

They add the previous answers to get their answers.

ps can u please give me brainly

You might be interested in
Gavin rolls a fair dice 48 times.<br> How many times would Gavin expect to roll an even number?
pantera1 [17]

Answer: The number of times Gavin expect to roll an even number =24

Step-by-step explanation:

Given: Numbers of a fair dice = 1, 2, 3, 4, 5, 6

even numbers = 2, 4, 6

odd numbers = 1, 3, 5

Probability of getting an even number = \dfrac{3}{6}=\dfrac12

If Gavin rolls a fair dice 48 times.

Then, the number of times Gavin expect to roll an even number = 48\times\dfrac12=24

Hence, the number of times Gavin expect to roll an even number =24

6 0
3 years ago
Suppose that the weight (in pounds) of an airplane is a linear function of the total amount of fuel (in gallons) in its tahk. Wh
kvasek [131]

Answer:

2002 pounds

Explanation:

To know the weight of the plane, we need to find an equation that relates the amount of fuel to the weight.

This equation can be founded using the following

y-y_1=m(x-x_1)

Where m is the slope, x1 is the number of gallons and y1 is the respective weight. So, replacing m = 6.0, x1 = 51 gallons and y1 = 2206 pounds, we get:

y-2206=6(x-51)

Now, we can solve for y

\begin{gathered} y-2206=6(x)-6(51) \\ y-2206=6x-306 \\ y=6x-306+2206 \\ y=6x+1900 \end{gathered}

Then, we can calculate the weight of an airplane with 17 gallons of fuel replacing x = 17 on the equation above

y = 6x + 1900

y = 6(17) + 1900

y = 102 + 1900

y = 2002

Therefore, the answer is 2002 pounds

5 0
1 year ago
Answer need help plz
satela [25.4K]
MAE - 48 = 36 x 2
mAE - 48 = 72
mAE = 120

Answer
120
4 0
4 years ago
Read 2 more answers
PLEASE HELP I WILL GIVE BRAINLEST AND 20 POINTS PLEASEEEE
rewona [7]

Answer:

Question 4: Which equation is parallel to the above equation and passes through the point (35, 30)

y= \frac{5}{7} x + 5  is the correct answer, I found this by inputting the x and y value of the coordinate (35, 30) onto the equation and solving for y-intercept since the slope of all equations is the same (since it's traveling parallel)

30 = \frac{5}{7} (35) + y\\30 = 25 + y\\5 = y

so the equation would be y= \frac{5}{7} x + 5

Question 5: Which equation is perpendicular to the above equation and passes through the point (35, 30)

y=\frac{-7}{5} x+79 is the correct answer, I found this using the same method as before, input coordinate values into the equation and solve for the y-intercept (The only thing changed from the last answer is the opposite reciprocal slope).

30 = \frac{-7}{5}(35) + y \\30 = -49 + y  \\79 = y

so the equation would be y=\frac{-7}{5} x+79

6 0
2 years ago
Two consecutive integers have a sum of 75. Find the integers.
Pie

Answer:

37 and 38

Step-by-step explanation:

let the consecutive integers be x-1 and x

If their sum is 75

x-1+x = 75

2x - 1 = 75

2x = 75+1

2x = 76

x = 76/2

x = 38

First integer = x - 1

First integer = 38-1 = 37

Second integer is 38

Hence the integers are 37 and 38

7 0
3 years ago
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