Answer:
AB = 13.89
Measure of angle A = 59.74°
Measure of angle B = 30.26°
Step-by-step explanation:
The given parameters are;
∠C = 90°
AC = 7
BC = 12
Part 1
Hence, the question has the dimensions of the two adjacent sides of the right angle (angle 90°)
From Pythagoras theorem, we have;
A² = B² + C²
Where, A is the opposite side to the right angle, hence;
In the ΔABC,
AB ≡ A
Therefore;
AB² = AC² + BC² = 7² + 12² = 193
∴ AB = √193 = 13.89
Part 2
∠A is the side opposite side BC such that by trigonometric ratios
![tan \angle A = \frac{Opposite \, side \, to \, angle \, A}{Adjacent \, side \, to \, angle \, A} = \frac{BC}{AC} = \frac{12}{7} = 1.714](https://tex.z-dn.net/?f=tan%20%5Cangle%20A%20%3D%20%5Cfrac%7BOpposite%20%5C%2C%20side%20%5C%2C%20%20to%20%5C%2C%20%20angle%20%5C%2C%20%20A%7D%7BAdjacent%20%20%5C%2C%20%20side%20%20%5C%2C%20to%20%20%5C%2C%20angle%20%5C%2C%20%20A%7D%20%20%3D%20%5Cfrac%7BBC%7D%7BAC%7D%20%3D%20%5Cfrac%7B12%7D%7B7%7D%20%3D%201.714)
∴ ∠A = Arctan(1.714) or tan⁻¹(1.714) = 59.74°
Part 3
∠B is found from knowing that the sum of the angles in a triangle = 180°
∴ ∠A + ∠B + ∠C = 180° which gives
59.74° + 90° + ∠B = 180°
Hence, ∠B = 180° - (59.74° + 90°) = 180° - 149.74° = 30.26°.