I'm not going to dignify this question with a response. xD
Answer:
Step-by-step explanation:
we know that
The <u>Least Common Multiple</u> (LCM) of a group of numbers is the smallest number that is a multiple of all the numbers.
we have
15,18 and 25
Decompose the numbers in prime factors
Multiply common and uncommon numbers with their greatest exponent
so
The LCM is equal to
FVAO=2500[((1+0.013/4)^(4*25)-1)/(0.013/4]
FVAO=294,847.29
The answer is c
Answer:
-54.3
Step-by-step explanation:
4(1.5−6.2)−4.5−31
=(4)(−4.7)−4.5−31
=−18.8−4.5−31
=−23.3−31
=−54.3
17) f(x) = 16/(13-x).
In order to find domain, we need to set denominator expression equal to 0 and solve for x.
And that would be excluded value of domain.
13-x =0
Adding x on both sides, we get
13-x +x = x.
13=x.
Therefore, domain is All real numbers except 13.
18).f(x) = (x-4)(x+9)/(x^2-1).
In order to find the vertical asymptote, set denominator equal to 0 and solve for x.
x^2 -1 = 0
x^2 -1^2 = 0.
Factoring out
(x-1)(x+1) =0.
x-1=0 and x+1 =0.
x=1 and x=-1.
Therefore, Vertical asymptote would be
x=1 and x=-1
19) f(x) = (7x^2-3x-9)/(2x^2-4x+5)
We have degrees of numberator and denominator are same.
Therefore, Horizontal asymptote is the fraction of leading coefficents.
That is 7/2.
20) f(x)=(x^2+3x-2)/(x-2).
The degree of numerator is 2 and degree of denominator is 1.
2>1.
Degree of numerator > degree of denominator .
Therefore, there would no any Horizontal asymptote.
