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Viefleur [7K]
3 years ago
10

Solve (5w+1)(5-w)=0 (If there is more than one solution, separate them with commas)

Mathematics
2 answers:
tester [92]3 years ago
7 0

problem decoded dude

thank and follow me

adell [148]3 years ago
4 0

Answer:

w=5, -1/5

Step-by-step explanation:

If you multiply a number by 0, you get 0, right?

So, all you have to do is make one paretheses equal to 0.

First case:

w=-1/5

(-1+1)(5+1/5)= 0(5+1/5)=0

Second case:

w=5

(25+1)(0)=0

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Answer:

19,600 Nm

Step-by-step explanation:

WD = mgh

= 40 × 9.8 × 50

= 19600 Nm

8 0
3 years ago
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Cos (90-theta) • cosec90-theta) =tano. How?​
denis-greek [22]

Answer:

<u>______________________________________________________</u>

<u>TRIGONOMETRY IDENTITIES TO BE USED IN THE QUESTION :-</u>

For any right angled triangle with one angle α ,

  • \cos (90 - \alpha  ) = \sin \alpha  or  \sin(90 - \alpha ) = \cos\alpha
  • cosec \: (90 - \alpha  ) = \sec\alpha   or  \sec(90 - \alpha ) = cosec\:\alpha

<u>SOME GENERAL TRIGNOMETRIC FORMULAS :-</u>

  • <u></u>\sin \alpha = \frac{1}{cosec \: \alpha }  or  cosec \: \alpha  = \frac{1}{\sin \alpha }
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<u>______________________________________________________</u>

Now , lets come to the question.

In a right angled triangle , let one angle be α (in place of theta) .

So , lets solve L.H.S.

\cos (90 - \alpha ) \times cosec(90 - \alpha )

=> sin\alpha  \times \sec\alpha

=> \sin\alpha  \times \frac{1}{\cos\alpha }

=> \frac{\sin\alpha }{\cos\alpha }

=> \tan\alpha = R.H.S.

∴ L.H.S. = R.H.S. (Proved)

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3 years ago
Factor by grouping.......
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Answer:

A. (7n-1) (8n-1)

Step-by-step explanation:

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Factor out 8n from the first group   and -1 from the second group

8n (7n-1)     -1(7n-1)

Factor out the (7n-1)

(7n-1) (8n-1)

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Step-by-step explanation:

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Nigel tried to solve an equation step by step
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Step-by-step explanation:

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