Answer:
Step-by-step explanation:
divide los números entre cuántos hermanos y cuántos euros
The cost of spices in US dollars is $5.45
The cost of spices in Indian rupees = 401.39 rupees
The exchange rate is
1 dollar:73.6500 rupees
So we have to exchange the Indian rupees to the US dollars
The cost of spices in Indian rupees = 401.39 rupees
The cost of spices in US dollars = The cost of spices in Indian rupees / 73.6500
Substitute the values in the equation and fins the cost of spices in US dollars
The cost of spices in US dollars = 401.39 / 73.6500
Divide the numbers
= $5.45
Hence, the cost of spices in US dollars is $5.45
Learn more about exchange rate here
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We can first get the percentage of the emergency room visits that involves an injury.
6 out of 10.
This will be (6/10)×100 = 60%
So, if there are 930 emergency room visits, the expected visits <span>included a prescription for medication is;
</span>
60% of 930 = 60/100 × 930
= 0.6 ×930
= 558
Hmmmm to convert from improper to mixed, simply do the division of both, the quotient gets upfront, the remainder as the numerator, for example,
how many times 3 goes into 81? well, 27 times, with a remainder of 0, thus
![\bf 27\frac{0}{3}](https://tex.z-dn.net/?f=%5Cbf%2027%5Cfrac%7B0%7D%7B3%7D)
how many times does 2 go into 29? well 14 times, with a remainder of 1, thus
Answer:
The value at x =3 is undefined for the given expression
Step-by-step explanation:
Given expression is ![\frac{2x^2+8x}{(x+4)(x^2-9)}](https://tex.z-dn.net/?f=%5Cfrac%7B2x%5E2%2B8x%7D%7B%28x%2B4%29%28x%5E2-9%29%7D)
To find for what value of x is undefined in the given expression :
![\frac{2x^2+8x}{(x+4)(x^2-9)}=\frac{2x(x+4)}{(x+4)(x^2-9)}](https://tex.z-dn.net/?f=%5Cfrac%7B2x%5E2%2B8x%7D%7B%28x%2B4%29%28x%5E2-9%29%7D%3D%5Cfrac%7B2x%28x%2B4%29%7D%7B%28x%2B4%29%28x%5E2-9%29%7D)
![=\frac{2x}{x^2-9}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B2x%7D%7Bx%5E2-9%7D)
![\frac{2x^2+8x}{(x+4)(x^2-9)}=\frac{2x}{x^2-9}](https://tex.z-dn.net/?f=%5Cfrac%7B2x%5E2%2B8x%7D%7B%28x%2B4%29%28x%5E2-9%29%7D%3D%5Cfrac%7B2x%7D%7Bx%5E2-9%7D)
If we put x=3 in the above expression we get
![\frac{2x}{x^2-9)}=\frac{2(3)}{3^2-9}](https://tex.z-dn.net/?f=%5Cfrac%7B2x%7D%7Bx%5E2-9%29%7D%3D%5Cfrac%7B2%283%29%7D%7B3%5E2-9%7D)
![=\frac{6}{9-9}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B6%7D%7B9-9%7D)
![=\frac{6}{0}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B6%7D%7B0%7D)
Therefore ![\frac{2x^2+8x}{(x+4)(x^2-9)}=\frac{6}{0}](https://tex.z-dn.net/?f=%5Cfrac%7B2x%5E2%2B8x%7D%7B%28x%2B4%29%28x%5E2-9%29%7D%3D%5Cfrac%7B6%7D%7B0%7D)
The value at x =3 is undefined for the given expression