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3 years ago

Is this right? Please help me

Mathematics

2 answers:

erma4kov [3.2K]3 years ago

7 0

Answer:

$\boxed {\mathfrak {B) 1.6}}$

Step-by-step explanation:

B) $r-value$ $cant$ $be$ $1.6$

$-1 \leq r\leq 1$

$-----$

poizon [28]3 years ago

5 0

Answer:

yeah its correct

Step-by-step explanation:

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32 + 64x - 40y (please factor it)

Lana71 [14]

The answer factored is
8(4+8x-5y)

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3 years ago

June worked at Panda Express over the summer making $11.50/hour. Complete the table to keep track of how much money he will be m

mel-nik [20]

11.50 x 1 = 11.50

11.50 x 2 = 23.00

11.50 x 3 = 34.50

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11.50 x 5 = 57.50

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3 years ago

Simplify :<br> 3n + 1 +5n + (-11)

PilotLPTM [1.2K]

8n-10 is the answer
(3n+5n)+(1-11)

6 0

3 years ago

Read 2 more answers

A circle has a circumference of

levacccp [35]

Answer:

Hope this helps you

The diameter is 1 unit

Step-by-step explanation:

The circumference is 3.14 units

C = pi * d

Using 3.14 for pi

3.14 = 3.14 d

Divide each side by 3.14

3.14/3.14 = 3.14 d/ 3.14

1 =d

7 0

3 years ago

Read 2 more answers

Use the chain rule to find dw/dt. w = ln x2 + y2 + z2 , x = 7 sin(t), y = 9 cos(t), z = 6 tan(t)

DENIUS [597]

By the chain rule,

$\dfrac{\mathrm dw}{\mathrm dt}=\dfrac{\partial w}{\partial x}\dfrac{\mathrm dx}{\mathrm dt}+\dfrac{\partial w}{\partial y}\dfrac{\mathrm dy}{\mathrm dt}+\dfrac{\partial w}{\partial z}\dfrac{\mathrm dz}{\mathrm dt}$

We have

$\dfrac{\partial w}{\partial x}=\dfrac{2x}{x^2+y^2+z^2}$
$\dfrac{\partial w}{\partial y}=\dfrac{2y}{x^2+y^2+z^2}$
$\dfrac{\partial w}{\partial z}=\dfrac{2z}{x^2+y^2+z^2}$

$\dfrac{\mathrm dx}{\mathrm dt}=7\cos t$
$\dfrac{\mathrm dy}{\mathrm dt}=-9\sin t$
$\dfrac{\mathrm dz}{\mathrm dt}=6\sec^2t$

So we have

$\dfrac{\mathrm dw}{\mathrm dt}=\dfrac2{x^2+y^2+z^2}\left(7x\cos t-9y\sin t+6z\sec^2t\right)$
$\dfrac{\mathrm dw}{\mathrm dt}=\dfrac{2\left(49\sin t\cos t-81\cos t\sin t+36\tan t\sec^2t\right)}{49\sin^2t+81\cos^2t+36\tan^2t}$
$\dfrac{\mathrm dw}{\mathrm dt}=\dfrac{8\sin t(9-16\cos^4t)}{\cos t(36+13\cos^2t+32\cos^4t)}$

3 0

4 years ago