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hodyreva [135]
3 years ago
11

Please help me with whole answer i give brainliest.

Mathematics
1 answer:
anastassius [24]3 years ago
7 0

Answer:

Step-by-step explanation:

15 < x + 8

x> 7

(Opened circle)

x + 8 <= 19

x <= 11

(Closed circle)

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Can someone help me with this ASAP please 50 points!!!
ella [17]

Answer:

a = 17 sqrt(2)

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

sin theta = opposite / hypotenuse

sin 45 = 17/a

Multiply each side by a

a sin 45 = 17

Divide each side by sin 45

a = 17 / sin 45

a = 17 / ( 1 / sqrt(2))

a = 17 sqrt(2)

7 0
3 years ago
in the diagram, AB is parallel to DE. Also, DE is drawn such that the length of DE is half the length of AB. If sin A=0.5, then
Ainat [17]

Answer:

I got sin E = 0.5

Thus answer choice C being the correct choice

Hope this helps ;)

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
The base of an aquarium with given volume V is made of slate and the sides are made of glass. If the slate costs seven times as
lubasha [3.4K]

Answer:

l = \sqrt[3]{\frac{2V}{7}}     b = \sqrt[3]{\frac{2V}{7}}       h = \sqrt[3]{\frac{49V}{4}}

Step-by-step explanation:

Represent the volume of the box with V and the dimensions with l, b and h.

The volume (V) is:

V = l * b * h

Make h the subject of the formula

h = \frac{V}{lb}

The surface area (S) of the aquarium is:

S = lb + 2(lh + bh)

Where lb represents the area of the base (i.e. slate):

The cost (C) of the surface area is:

C = 7 * lb + 1 * 2(lh + bh)

C = 7lb + 2(lh + bh)

C = 7lb + 2h(l + b)

Substitute \frac{V}{lb} for h in the above equation

C = 7lb + 2*\frac{V}{lb}(l + b)

C = 7lb + \frac{2V}{lb}(l + b)

C = 7lb + \frac{2V}{b} + \frac{2V}{l}

Differentiate with respect to l and with respect to b

C_l=7b - \frac{2V}{l^2} =0

C_b=7l - \frac{2V}{b^2} =0

To solve for b and l, we equate both equations and set l to b (to minimize the cost)

7b - \frac{2V}{l^2}=7l - \frac{2V}{b^2}

7l - \frac{2V}{l^2}=7b - \frac{2V}{b^2}

By comparison:

l =b

C_l=7b - \frac{2V}{l^2} =0 becomes

7l - \frac{2V}{l^2}=0

7l = \frac{2V}{l^2}

Cross Multiply

7l^3 = 2V

Solve for l

l^3 = \frac{2V}{7}

l = \sqrt[3]{\frac{2V}{7}}

Recall that: l =b

b = \sqrt[3]{\frac{2V}{7}}

Also recall that:

h = \frac{V}{lb}

h = \frac{V}{\sqrt[3]{\frac{2V}{7}}*\sqrt[3]{\frac{2V}{7}}}

h = \frac{V}{\sqrt[3]{\frac{4V^2}{49}}}

Apply law of indices

h = \sqrt[3]{\frac{49V^3}{4V^2}}

h = \sqrt[3]{\frac{49V}{4}}

The dimension that minimizes the cost of material of the aquarium is:

l = \sqrt[3]{\frac{2V}{7}}     b = \sqrt[3]{\frac{2V}{7}}       h = \sqrt[3]{\frac{49V}{4}}

8 0
3 years ago
What's 3 times the 6th power of 10
s344n2d4d5 [400]
It would be 3,000,000 because 10^6 equals to 1,000,000.

Multiply 1 million by 3 equals 3 million.
8 0
3 years ago
Please answer both tysm
Kipish [7]

Answer:

B for 2

A, C, D, and F for 1

7 0
2 years ago
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