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krok68 [10]
3 years ago
15

HELPPPPP...........

Mathematics
1 answer:
Blababa [14]3 years ago
6 0

Answer:

3 and 4 are the only ones that are right angles.

Step-by-step explanation:

A^2+B^2=C^2

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Write the expression in standard form. -2(8m + 3)​
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Answer:

-16m-6

Step-by-step explanation:

use distributive property, you get -16m-6

I hope this helped, and if my answer was right, please mark this as brainliest! Thank you!

4 0
3 years ago
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Find f(2) if f(x) = (x + 1)2.<br><br><br> 1. 9<br> 2. 6<br> 3. 5
kolezko [41]

Answer: f(2) = 6

Step-by-step explanation: In this problem, we are given the function

f (x) = (x + 1) 2 and we are asked to find f(2). In other words, if we put an "x" into our function, we get a (x + 1) 2 out.

f we put a 2 into the function, we get f(2) =  (2 + 1) 2 out. Now all we have to do is simplify on the right side.

2 + 1 gives us 3 and if we multiply 3 by 2, we get a product of 6.

Therefore, f(2) is 6.

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3 years ago
Kendall scored 3 times as many points as Abdul scored in a basketball game. Otis scored 5 more points than Abdul
Readme [11.4K]
Answer: it’s C
Because Kendall scored 3 times abdul
7 0
3 years ago
CAN SOMEONE HELP MEEEEEEEEEE
Debora [2.8K]

Answer:

c =  \sqrt{146}   \\ x = 48°

5 0
3 years ago
) One year, professional sports players salaries averaged $1.5 million with a standard deviation of $0.9 million. Suppose a samp
Nutka1998 [239]

Answer:

Probability that the average salary of the 400 players exceeded $1.1 million is 0.99999.

Step-by-step explanation:

We are given that one year, professional sports players salaries averaged $1.5 million with a standard deviation of $0.9 million.

Suppose a sample of 400 major league players was taken.

<em>Let </em>\bar X<em> = sample average salary</em>

The z-score probability distribution for sample mean is given by;

                 Z = \frac{ \bar X -\mu}{{\frac{\sigma}{\sqrt{n} } }} }  ~ N(0,1)

where, \mu = mean salary = $1.5 million

            \sigma = standard deviation = $0.9 million

             n = sample of players = 400

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

So, probability that the average salary of the 400 players exceeded $1.1 million is given by = P(\bar X > $1.1 million)

    P(\bar X > $1.1 million) = P( \frac{ \bar X -\mu}{{\frac{\sigma}{\sqrt{n} } }} } >  \frac{ 1.1-1.5}{{\frac{0.9}{\sqrt{400} } }} } ) = P(Z > -8.89) = P(Z < 8.89)

<em>Now, in the z table the maximum value of which probability area is given is for critical value of x = 4.40 as 0.99999. So, we can assume that the above probability also has an area of 0.99999 or nearly close to 1.</em>

Therefore, probability that the average salary of the 400 players exceeded $1.1 million is 0.99999.

4 0
3 years ago
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