Question

250 mL of water is collected during a combustion reaction. The temperature in the

Answer 1

Answer:

0.011 moles

Explanation:

Applying,

PV = nRT.................... Equation 1

Where P = Pressure, V = Volume, n = number of moles, R = Molar gas constant, T = Temperature.

Make n the subject of the equation

n = PV/RT.................. Equation 2

From the question,

Given: P = 105 kPa = (105×0.00986923) = 1.036 atm, V = 250 mL = 0.25 L, T = 23 °C = (273+23) = 296 °C

Constant: R = 0.082 atm.dm³/K.mol

Substitute these values into equation 2

n = (1.036×0.25)/(0.082×296)

n = 0.011 moles