Explanation:
There are non-polar side chains also present in alanine. And, these non-polar side chains are involved in some hydrophobic interactions in active sideand then it changes into polar amino acid glutamate that will destroy the hydrophobic interaction.
Whereas in glycine there is only hydrogen present in the side chain therefore, it will not affect much.
A chemist dilutes a 1.0 ml sample of 2.0M KNO₃ by adding water to it. If the concentration of the solution that is obtained is 0.0080 m, then its volume is 250mL.
<h3>How do we calculate volume?</h3>
Volume for the given equation will be calculated by using the below equation as:
M₁V₁ = M₂V₂, where
M₁ = molarity of KNO₃ = 2M
V₁ = volume of KNO₃ = 1mL
M₂ = molarity of final solution = 0.0080M
V₂ = volume of final solution = ?
On putting these values on the above equation, we get
V₂ = (2)(1) / (0.0080) = 250mL
Hence option (2) is correct.
To know more about molarity, visit the below link:
brainly.com/question/24305514
Answer:
0.0554 moles of NaCl are produced from the reaction of 1.67*10²² molecules of Na₂CO₃ with excess HCl.
Explanation:
The balanced reaction is:
Na₂CO₃ + 2 HCl → 2 NaCl + CO₂ + H₂O
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of each compound participate in the reaction:
- Na₂CO₃: 1 mole
- HCl: 2 moles
- NaCl: 2 moles
- CO₂: 1 mole
- H₂O: 1 mole
On the other hand, Avogadro's Number is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023*10²³ particles per mole. Avogadro's number applies to any substance.
In this case, you can apply the following rule of three: if 6.023*10²³ molecules of Na₂CO₃ are contained in 1 mole, 1.67*10²² molecules will be contained in how many moles?

amount of moles= 0.0277 moles
In this case, you can apply the following rule of three: if by stoichiometry 1 mole of Na₂CO₃ produces 2 moles of NaCl, 0.0277 moles of Na₂CO₃ will produce how many moles of NaCl?

amount of moles of NaCl= 0.0554 moles
<u><em>0.0554 moles of NaCl are produced from the reaction of 1.67*10²² molecules of Na₂CO₃ with excess HCl.</em></u>
Answer:
The graph represents an endothermic reaction.
The products have more energy than the reactants.
80kJ
160kJ
80kJ
160kJ