is the solubility of the gas when it exerts a partial pressure of 92.4kPa.
<h3>What is Henry's law?</h3>
Mathematically, we can get this from Henry's law
From Henry law;
Concentration = Henry constant × partial pressure
Thus Henry constant = 
Henry constant = 
Hence, is the solubility of the gas when it exerts a partial pressure of 92.4kPa.
Learn more about the Henry's law here:
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Answer:
E. 6.9 E-7 M
Explanation:
0.10M 0.10M 0.10M
eq: S S 2S + 0.1
∴ Ksp = 6.9 E-9 = [Mg2+][F-]² = (S)(2S+0.1)²
if we compared the concentration ( 0.1 M ) with the Ksp ( 6.9 E-9 ); then we can neglect the solubility as adding:
⇒ Ksp = 6.9 E-9 = (S)(0.1)² = 0.01S
⇒ S = 6.9 E-9 / 0.01 = 6.9 E-7 M
