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777dan777 [17]
2 years ago
12

BRANLIEST NO EXPLANATION NEEDED.

Chemistry
2 answers:
alexandr402 [8]2 years ago
6 0

Answer:

Smashing the cube into pieces

Explanation:

The reason for this is that if we were to smash the cube we would have a larger surface area which means more manganese oxide would be dissolving per second which means we would have a faster reaction rate where if we were to chill the peroxide it would dissolve slower which in turn slows the reaction. For example a spoonful of granulated sugar will react with water faster than a sugar cube.

Leviafan [203]2 years ago
3 0

Answer:

d. smashing the cube into pieces.

Explanation:

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Given that a for HBrO is 2. 8×10^−9 at 25°C. What is the value of b for BrO− at 25°C?
lara [203]

If Ka for HBrO is 2. 8×10^−9 at 25°C, then the value of Kb for BrO− at 25°C is 3.5× 10^(-6).

<h3>What is base dissociation constant? </h3>

The base dissociation constant (Kb) is defined as the measurement of the ions which base can dissociate or dissolve in the aqueous solution. The greater the value of base dissociation constant greater will be its basicity an strength.

The dissociation reaction of hydrogen cyanide can be given as

HCN --- (H+) + (CN-)

Given,

The value of Ka for HCN is 2.8× 10^(-9)

The correlation between base dissociation constant and acid dissociation constant is

Kw = Ka × Kb

Kw = 10^(-14)

Substituting values of Ka and Kw,

Kb = 10^(-14) /{2.8×10^(-9) }

= 3.5× 10^(-6)

Thus, we find that if Ka for HBrO is 2. 8×10^−9 at 25°C, then the value of Kb for BrO− at 25°C is 3.5× 10^(-6).

DISCLAIMER: The above question have mistake. The correct question is given as

Question:

Given that Ka for HBrO is 2. 8×10^−9 at 25°C. What is the value of Kb for BrO− at 25°C?

learn more about base dissociation constant:

brainly.com/question/9234362

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Does anybody know how to do this if so please help !
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easier formula

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