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3 years ago

If a combustion reaction is reversed, what needs to happen to the H value?

Chemistry

1 answer:

zmey [24]3 years ago

3 0

Answer:

decomposition of the h value

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What is the product of the reaction of (S)-2-bromobutane with sodium methoxide in acetone?

Serggg [28]

Answer:

2-methoxybutane

Explanation:

This reaction is an example of Nucleophilic substitution reaction. Also, the reaction of (S)-2-bromobutane with sodium methoxide in acetone, is bimolecular nucleophilic substitution (SN2). The reaction equation is given below.

(S)-2-bromobutane + sodium methoxide (in acetone) → 2-methoxybutane

7 0

2 years ago

. A bright violet line occurs at 435.8 nm in the emission spectrum of mercury vapor. What amount of energy, in joules, must be r

Tom [10]

Answer : The energy released by an electron in a mercury atom to produce a photon of this light must be, $4.56\times 10^{-19}J$

Explanation : Given,

Wavelength = $435.8nm=435.8\times 10^{-9}m$

conversion used : $1nm=10^{-9}m$

Formula used :

$E=h\times \nu$

As, $\nu=\frac{c}{\lambda}$

So, $E=h\times \frac{c}{\lambda}$

where,

$\nu$ = frequency

h = Planck's constant = $6.626\times 10^{-34}Js$

$\lambda$ = wavelength = $435.8\times 10^{-9}m$

c = speed of light = $3\times 10^8m/s$

Now put all the given values in the above formula, we get:

$E=(6.626\times 10^{-34}Js)\times \frac{(3\times 10^{8}m/s)}{(435.8\times 10^{-9}m)}$

$E=4.56\times 10^{-19}J$

Therefore, the energy released by an electron in a mercury atom to produce a photon of this light must be, $4.56\times 10^{-19}J$

3 0

3 years ago

The three major groups on the peridoic table are the ____

qaws [65]

Metals on the left side, metalloids on the staircase, nonmetals on right side

5 0

3 years ago

Consider the reversible reaction A ( g ) − ⇀ ↽ − B ( g ) Which K values would indicate that there is more B than A at equilibriu

oksano4ka [1.4K]

Answer:

5000 and $8\times 10^{7}$ indicate that there is more B than A at equilibrium

Explanation:

For the given reaction: $K=\frac{[B]}{[A]}$

where [B] and [A] represents equilibrium concentration B and A respectively. K represents equilibrium constant

More B than A at equilibrium means, [B] > [A]

So, $K=\frac{[B]}{[A]}>1$

As, both 5000 and $8\times 10^{7}$ are greater than 1 therefore these two K values indicate that there is more B than A at equilibrium

4 0

2 years ago

What is the probability of a<br> short plant in the cross<br> between a Tt and a tt plant?

kondaur [170]

75% would be your answer since the lower letter represents a shorter plant

7 0

2 years ago