Answer:
Step-by-step explanation:
Hello!
Your study variable is X: "number of ColorSmart-5000 that didn't need repairs after 5 years of use, in a sample of 390"
X~Bi (n;ρ)
ρ: population proportion of ColorSmart-5000 that didn't need repairs after 5 years of use. ρ = 0.95
n= 390
x= 303
sample proportion ^ρ: x/n = 303/390 = 0.776 ≅ 0.78
Applying the Central Limit Theorem you approximate the distribution of the sample proportion to normal to obtain the statistic to use.
You are asked to estimate the population proportion of televisions that didn't require repairs with a confidence interval, the formula is:
^ρ±
* √[(^ρ(1-^ρ))/n]
=
= 2.58
0.78±2.58* √[(0.78(1-0.78))/390]
0.0541
[0.726;0.834]
With a confidence level of 99% you'd expect that the interval [0.726;0.834] contains the true value of the proportion of ColorSmart-5000 that didn't need repairs after 5 years of use.
I hope it helps!
1 out of 2 outcomes ! i hope i helped !
Answer:
Answer is below
Step-by-step explanation:
Idk if it 430 or 436 but if it is 436.051 that goes first
then 435.786
435.100
if it is 430.051 then it is in the order of
435.781
435.100
430.051
Looks like we're given

which in three dimensions could be expressed as

and this has curl

which confirms the two-dimensional curl is 0.
It also looks like the region
is the disk
. Green's theorem says the integral of
along the boundary of
is equal to the integral of the two-dimensional curl of
over the interior of
:

which we know to be 0, since the curl itself is 0. To verify this, we can parameterize the boundary of
by


with
. Then


Answer:
6
Step-by-step explanation:
4 = 12/3
12/3 divided by 2/3 = 6
2/3
2/3
2/3
2/3
2/3
2/3
+
______
12/3
The answer is 6