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sertanlavr [38]
3 years ago
10

A board measuring 7.2 feet must be cut into three equal pieces

Mathematics
1 answer:
Softa [21]3 years ago
7 0
Each piece would be about 2.4 feet long. You find this out by dividing 7.2 and 3 which comes out to 2.4
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Which of the following equations is an example of inverse variation between
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Answer:

B

Step-by-step explanation:

Any inversely proportional equation is of the form y=k/x.

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The sum of three consecutive numbers is 72 what is the smallest of the numbers
mylen [45]

Answer:

23

Step-by-step explanation:

Suppose,

the first number = x

the second number = x+1

the third number = x+1+1 = x+2

Question wise,

x+x+1+x+2 = 72

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3x = 72-3 = 69

x = 69/3 = 23

so the numbers are,

23,(23+1)=24 and (23+2)=25

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Write each expression in simplest form. (x²/x⁻¹¹)¹/₃
aleksklad [387]

The result of simplifying the expression (x²/x⁻¹¹)¹/₃ using the exponent rules is \sqrt[3]{}(x¹³)

To solve this exercise we have to resolve algebraic operations following the exponent rules.

(x²/x⁻¹¹)¹/₃

Using the quotient rule that indicates that: the exponent result will be the subtraction of these exponents, we have:

(x⁽²⁻⁽⁻¹¹⁾)¹/₃

(x⁽²⁺¹¹⁾)¹/₃

(x¹³)¹/₃

Using the power of a power rule that indicates that: the exponent result will be the multiplication of these powers, we have:

x⁽¹³*¹/₃⁾

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As we have a fractional exponent, you must convert the exponent to root:

\sqrt[3]{}(x¹³)

<h3>What is an exponent?</h3>

In mathematics an exponent is the number of time that a number, called (base) is multiplied by itself. It is also called, power or index.

Example: 3² = 3*3 = 9

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8 0
1 year ago
Problem 10: A tank initially contains a solution of 10 pounds of salt in 60 gallons of water. Water with 1/2 pound of salt per g
AysviL [449]

Answer:

The quantity of salt at time t is m_{salt} = (60)\cdot (30 - 29.833\cdot e^{-\frac{t}{10} }), where t is measured in minutes.

Step-by-step explanation:

The law of mass conservation for control volume indicates that:

\dot m_{in} - \dot m_{out} = \left(\frac{dm}{dt} \right)_{CV}

Where mass flow is the product of salt concentration and water volume flow.

The model of the tank according to the statement is:

(0.5\,\frac{pd}{gal} )\cdot \left(6\,\frac{gal}{min} \right) - c\cdot \left(6\,\frac{gal}{min} \right) = V\cdot \frac{dc}{dt}

Where:

c - The salt concentration in the tank, as well at the exit of the tank, measured in \frac{pd}{gal}.

\frac{dc}{dt} - Concentration rate of change in the tank, measured in \frac{pd}{min}.

V - Volume of the tank, measured in gallons.

The following first-order linear non-homogeneous differential equation is found:

V \cdot \frac{dc}{dt} + 6\cdot c = 3

60\cdot \frac{dc}{dt}  + 6\cdot c = 3

\frac{dc}{dt} + \frac{1}{10}\cdot c = 3

This equation is solved as follows:

e^{\frac{t}{10} }\cdot \left(\frac{dc}{dt} +\frac{1}{10} \cdot c \right) = 3 \cdot e^{\frac{t}{10} }

\frac{d}{dt}\left(e^{\frac{t}{10}}\cdot c\right) = 3\cdot e^{\frac{t}{10} }

e^{\frac{t}{10} }\cdot c = 3 \cdot \int {e^{\frac{t}{10} }} \, dt

e^{\frac{t}{10} }\cdot c = 30\cdot e^{\frac{t}{10} } + C

c = 30 + C\cdot e^{-\frac{t}{10} }

The initial concentration in the tank is:

c_{o} = \frac{10\,pd}{60\,gal}

c_{o} = 0.167\,\frac{pd}{gal}

Now, the integration constant is:

0.167 = 30 + C

C = -29.833

The solution of the differential equation is:

c(t) = 30 - 29.833\cdot e^{-\frac{t}{10} }

Now, the quantity of salt at time t is:

m_{salt} = V_{tank}\cdot c(t)

m_{salt} = (60)\cdot (30 - 29.833\cdot e^{-\frac{t}{10} })

Where t is measured in minutes.

7 0
3 years ago
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