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2 years ago

Identify the terms, like terms, coefficients, and constants in each expression.

Mathematics

2 answers:

astra-53 [7]2 years ago

5 0

Answer:

2. Like terms: 5a 4. Lt: 4y, and y

coefficient: 2,-7 coefficient: 4, -3

Constant: 2,-7 constant: 4

3. like terms: 3h, 2h, and 6h can you follow these and do the remaining??

if no, I'll help u

coefficient: 3,2,6

constant: 9

Sever21 [200]2 years ago

3 0

2. Like terms :5a
Coefficient:5
Constant: 7

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Using the digits 1, 2, 3, 4, 5, 6, 7, and 9, make 4 two-digit prime numbers. What is the sum of those four prime numbers?

mr_godi [17]

Answer:

13, 17, 19, and 23

Step-by-step explanation:

13+17+19+23=72

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2 years ago

X=5y: 2x+5y=60 A) 10,4 B) 15,4 C) 20,4 D) 25,4

elena-14-01-66 [18.8K]

Answer:

C) 20, 4

Step-by-step explanation:

X = 5y

2x + 5y = 60

substitute in 5y for x: 2(5y) + 5y = 60

10y + 5y = 60

15y = 60

y = 4

x = 5y

x = 5(4) = 20

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A researcher compares the effectiveness of two different instructional methods for teaching physiology. A sample of 178 students

xxTIMURxx [149]

Answer:

critical value = 1.645

The 90% confidence interval = ( -22.62, -17.58)

Step-by-step explanation:

Given that:

the sample size $n_1$ = 178

the sample size $n_2$ = 226

the sample mean $\overline x_1$ = 54.4

the sample mean $\overline x_2$ = 74.5

population standard deviation $\sigma_1$ = 18.58

population standard deviation $\sigma_2$ = 9.52

level of significance ∝ = 1 - 0.90 = 0.10

The critical value for $Z_{\alpha/2} = Z _{0.10/2} = Z_{0.005}$ is 1.645

For the construction of our confidence interval, we use 90% since that is used to find the critical value.

∴

The margin of error = $Z \times\sqrt{\dfrac{\sigma_1^2}{n_1} + \dfrac{\sigma_2^2}{n_2}}$

$1.645 \times\sqrt{\dfrac{18.58^2}{178} + \dfrac{9.52^2}{226}}$

$1.645 \times\sqrt{\dfrac{345.2164}{178} + \dfrac{90.6304}{226}}$

$1.645 \times\sqrt{2.34042}$

$\simeq$ 2.52

The lower limit = $( \overline x_1 - \overline x_2) - (M.O.E)$

= ( 54.4-74.5) - (2.52)

= -20.1 - 2.52

= -22.62

The upper limit = $( \overline x_1 - \overline x_2) + (M.O.E)$

= ( 54.4-74.5) + (2.52)

= -20.1 + 2.52

= -17.58

The 90% confidence interval = ( -22.62, -17.58)

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