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elena-s [515]
3 years ago
6

Which of the following ordered pairs could not be included in this set if its a function? (-4,2) (3,6) (4,3) (?,?)

Mathematics
1 answer:
Debora [2.8K]3 years ago
8 0

Given:

The set of ordered pair (-4,2), (3,6), (4,3), (?,?).

To find:

The ordered pairs that could not be included in this set if its a function.

Solution:

We know that, a relation or a set of ordered pairs is a function if there exist a unique output (y-value) for each input (x-value).

If (-4,-3) point is included in the given set of ordered pair, then we have y=-3,2 for x=-4.

Since there are more than one output value at x=-4, therefore the given set of ordered pairs will not be a functions after including the point (-4,-3).

If points (1,2), (3,6) and (-3,6) are included in the given set of ordered pair, then there exist a unique output for each input.

So, the given set of ordered pairs will be a functions after including the points (1,2), (3,6) and (-3,6).

Therefore, the correct option is A.

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in this problem we have

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substitute in the formula above

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3 years ago
Please help. Will give Brainliest.
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Answer:

x = 0

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x = -2/3

Step-by-step explanation:

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3 years ago
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pychu [463]

Given:

Consider the given expression is:

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To find:

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Solution:

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Taking LCM, we get

=\dfrac{10(h+f)+15(f+k)+6(4h-k)}{30}

=\dfrac{10h+10f+15f+15k+24h-6k}{30}

=\dfrac{34h+25f+9k}{30}

Therefore, the required simplified fraction for the given expression is \dfrac{34h+25f+9k}{30}.

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3 years ago
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Step-by-step explanation:

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