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Alik [6]
3 years ago
8

Help on horizontal asymptote!

Mathematics
2 answers:
user100 [1]3 years ago
7 0

Answer:

A. None

Step-by-step explanation:

They are no horizontal asymptotes. I get helped from another website when comes to graphs and looking for asymptotes. Good luck on your exam!

Westkost [7]3 years ago
5 0

Answer:  A. none

<u>Step-by-step explanation:</u>

There are three rules when finding the horizontal asymptote (H.A.)

Consider "m" as the degree of the numerator and "n" as the degree of the denominator.

Rules:

  1. m > n: no H. A (use long division to find the slant asymptote)
  2. m = n: H.A. is y = leading coefficient of m ÷ leading coefficient of n
  3. m < n: H.A. is y = 0

In the equation given, the numerator is x⁵ + ... and the denominator is x⁴ + ...

m = 5, n = 4

m > n so there is no H.A

<em>but you can use long division to find the Slant Asymptote.</em>

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So far, this eliminates the first proof table because in this table, the last line says "angle c and angle h are supplementary" which is not what we want to end up with. We want the last line to say "angle b and angle h are supplementary".

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