Help on horizontal asymptote!
2 answers:
Answer:
A. None
Step-by-step explanation:
They are no horizontal asymptotes. I get helped from another website when comes to graphs and looking for asymptotes. Good luck on your exam!
Answer: A. none
<u>Step-by-step explanation:</u>
There are three rules when finding the horizontal asymptote (H.A.)
Consider "m" as the degree of the numerator and "n" as the degree of the denominator.
Rules:
- m > n: no H. A (use long division to find the slant asymptote)
- m = n: H.A. is y = leading coefficient of m ÷ leading coefficient of n
- m < n: H.A. is y = 0
In the equation given, the numerator is x⁵ + ... and the denominator is x⁴ + ...
m = 5, n = 4
m > n so there is no H.A
<em>but you can use long division to find the Slant Asymptote.</em>
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230
because 5x23 is 115 x 2 which is 230
I’m not sure i understand your question, could you send a picture of the question ??? i want to help you out ☝
Answer:
20%
Step-by-step explanation:
4+3+7=14
14÷7=2
2×10=20
If I am wrong please tell me I haven't had to do this me method in 3 years
1. added four to both sides
2. divided both sides by two
Option (b) is your correct answer.
Step-by-step explanation:

Given Trigonometric expression is

So, on rationalizing the denominator, we get

We know,

So, using this, we get

We know,

So, using this identity, we get


<u>Hence, </u>
