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nasty-shy [4]
3 years ago
13

Which expression is equivalent to the following?

Mathematics
1 answer:
xeze [42]3 years ago
3 0

Step-by-step explanation:

\sin^{4}x  \:  -  \cos^{4} x = (\sin^{2}x)^{2}  - (\cos^{2}x)^{2}

= (\sin^{2}x)^{2}  - (1 - \sin^{2}x)^{2}

= \sin^{4}x - (1 - 2\sin^{2}x + \sin^{4}x)

= 2\sin^{2}x - 1

=  - \cos2x

Note: I used the identity

{ \sin }^{2} x =  \frac{1}{2} (1 -  \cos \: 2x)

for the last step.

PS. I love proving trigonometric identities!

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You and a friend are playing a game by tossing two coins. If both coins land on heads,
tatyana61 [14]

Answer Yes it is a fair game

Step-by-step explanation:

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2 years ago
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Find the area and the circumference of a circle with radius 6 cm.
ozzi

Step-by-step explanation:

radius=6cm.

π=22 over 7

circumference=2πr

circumference=2×22 over7×6

circumference=51.04cm

7 0
2 years ago
Solve for y.<br> 8+4y= -8
Andrew [12]

Answer:

-4

Step-by-step explanation:

8+4y= -8

4y= -8 -8

4y= -16

divide both sides by the coeffient of the variable. in this case divide both sides by 4

y=-4

7 0
3 years ago
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Draw a line representing the "run" and a line representing the "rise" of the line. State the slope of the line in simplest form.
Igoryamba

Answer:

The answer is "\bold{\frac{9}{13}}"

Step-by-step explanation:

In this question, the image file is missing, which is defined in the attached file. please find it.

\to raise= y_2-y_1

             =-1-(-10)\\\\=-1+10\\\\=9

\to run= x_2-x_1

          =9-(-4)\\\\=9+4\\\\=13

\to \text{formula for slope} =\frac{rise}{run} =\frac{9}{13}

7 0
3 years ago
Construct a quadratic polynomial whose zeroes are negatives of the zeroes of the
sp2606 [1]

Given:

The given quadratic polynomial is :

x^2-x-12

To find:

The quadratic polynomial whose zeroes are negatives of the zeroes of the given polynomial.

Solution:

We have,

x^2-x-12

Equate the polynomial with 0 to find the zeroes.

x^2-x-12=0

Splitting the middle term, we get

x^2-4x+3x-12=0

x(x-4)+3(x-4)=0

(x+3)(x-4)=0

x=-3,4

The zeroes of the given polynomial are -3 and 4.

The zeroes of a quadratic polynomial are negatives of the zeroes of the given polynomial. So, the zeroes of the required polynomial are 3 and -4.

A quadratic polynomial is defined as:

x^2-(\text{Sum of zeroes})x+\text{Product of zeroes}

x^2-(3+(-4))x+(3)(-4)

x^2-(-1)x+(-12)

x^2+x-12

Therefore, the required polynomial is x^2+x-12.

4 0
3 years ago
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