I'm assuming that you meant:
1
f(x) = -------- and that you want to find the value of x at which f(x) = h(x).
x+1
Of course you could create a table for each f(x) and h(x), but setting f(x)=h(x) and solving for x algebraically would be faster and more efficient:
1
f(x) = -------- = 2x + 3 = h(x). Then 1 = (x+1)(2x+3) = 2x^2 + 3x + 2x + 3
x+1
or 1 = 2x^2 + 5x + 3, or 2x^2 + 5x + 2 = 0.
This is a quadratic equation with a=2, b=5 and c=2. The discriminant is b^2-4ac, or 5^2-4(2)(2), OR 25-16= 9.
Thus, the roots are
-5 plus or minus sqrt(9)
x = ------------------------------------
2(2)
-5 plus or minus 3
= ----------------------------------
4
= {-1/2, -2}
Thus, f(x) = h(x) at both x=-1/2 and x= -2.
First of all, to find the slope, you need to subtract the y's in the numerator over the x's in the denominator. Then you use Y-Y₁=slope(X-X₁) using either of the two points. If you want to simplify it further into slope-intercept form, you need to distribute on the right side of the equation.
Well then the answer is
80 grams
Answer: r≤10.4
Step-by-step explanation:
Initial depth - 12.8 feet
Maximum depth reached - 49.2 feet
49.2-12.8= 36.4 feet (maximum descent that the scuba diver can make)
Rate = Distance ÷ time
Distance - 36.4 feet
Time - 3.5 minutes
r=
r= 10.4
As r is the maxmimum rate found, r cannot be greater than 10.4, so r must be less than or equal to 10.4.
Therefore, r≤10.4
Answer:
The correct option is B. The area of the figure is 40.4 units².
Step-by-step explanation:
The line AB divides the figure in two parts one is a rectangle and another is semicircle.
The distance formula is
The length of AB is
The length of AD is
Since AB=AD, therefore ABCD is a square. The area of the of square is
The area of square is 29 units².
The area of a semicircle is
Since AB is the diameter of the semicircle, therefore the radius of the semicircle is
The area of the semicircle is
The area of the figure is
Therefore the area of the figure is 40.4 units². Option B is correct.