Answer:
1.544*10⁹ Linebackers would be required in order to obtain the same density as an alpha particle
Step-by-step explanation:
Assuming that the pea is spherical ( with radius R= 0.5 cm= 0.005 m), then its volume is
V= 4/3π*R³ = 4/3π*R³ = 4/3*π*(0.005 m)³ = 5.236*10⁻⁷ m³
the mass in that volume would be m= N*L (L= mass of linebackers=250Lbs= 113.398 Kg)
The density of an alpha particle is ρa= 3.345*10¹⁷ kg/m³ and the density in the pea ρ will be
ρ= m/V
since both should be equal ρ=ρa , then
ρa= m/V =N*L/V → N =ρa*V/L
replacing values
N =ρa*V/L = 3.345*10¹⁷ kg/m³ * 5.236*10⁻⁷ m³ /113.398 Kg = 1.544*10⁹ Linebackers
N=1.544*10⁹ Linebackers
Answer:
D. 50
Step-by-step explanation:
a = 90° (angle subtended in semicircle)
a + c + 40° = 180° (by angle sum postulate of a triangle)
90° + c + 40° = 180°
c + 130° = 180°
c = 180° - 130°
c = 50°
To solve the absolute value equation you first need to get everything not in the absolute value bars to the other side of the equation.
Step 1) Divide by 4
|n+8| = 14
*Remember: when solving absolute value equations, you make what the expression (n+8) is equal to negative and positive. Not the other way around.
Step 2) Make two equations
n+8 = 14
n+8 = -14
Solve and you'll see that n= 6 and -22
