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3 years ago

if you get 24 dollars ever week and you save 2/3 of it how much have you been saving i need help please

Mathematics

2 answers:

love history [14]3 years ago

3 0

Answer:

I believe your answer is 16

mariarad [96]3 years ago

3 0

Answer:

Step-by-step explanation:well it depends how many weeks you saved it for? So if a teacher wrote that on a test tell her what I told you

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Louis is playing a video game. He begins with an initial score of 300 points but loses 120 points throughout the game. He repres

elixir [45]

Answer:

300 + (-)120

Step-by-step explanation:

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3 years ago

How many terms are there in a geometric series if the first terms is 2, the common ratio is 4, and the sum of the series is 2,73

arsen [322]

The sum of n terms of a geometric series is given by
$S_{n}=a_{1}\dfrac{r^{n}-1}{r-1}$

Substituting the given numbers, you have
$2730=2\dfrac{4^{n}-1}{4-1}\\\\2730\dfrac{3}{2}=4^{n}-1\\\\4096=4^{n}\\\\\dfrac{\log(4096)}{\log(4)}=n=6$

There are 6 terms in the series.

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3 years ago

How many pennies are on the chessboard? 264 264 – 1 264 – 232

ale4655 [162]

18,446,744,073,709,551,615 pennies

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3 years ago

Read 2 more answers

2 tan 30°<br>II<br>1 + tan- 300

shusha [124]

Question:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$

Answer:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= sin(60^{\circ})$

Step-by-step explanation:

Given

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$

Required

Simplify

In trigonometry:

$tan(30^{\circ}) = \frac{1}{\sqrt{3}}$

So, the expression becomes:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2 * \frac{1}{\sqrt{3}}}{1 + (\frac{1}{\sqrt{3}})^2}$

Simplify the denominator

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2 * \frac{1}{\sqrt{3}}}{1 + \frac{1}{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\frac{2}{\sqrt{3}}}{1 + \frac{1}{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\frac{2}{\sqrt{3}}}{ \frac{3+1}{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\frac{2}{\sqrt{3}}}{ \frac{4}{3}}$

Express the fraction as:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2}{\sqrt 3} / \frac{4}{3}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2}{\sqrt 3} * \frac{3}{4}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{1}{\sqrt 3} * \frac{3}{2}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{3}{2\sqrt 3}$

Rationalize

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{3}{2\sqrt 3} * \frac{\sqrt{3}}{\sqrt{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{3\sqrt{3}}{2* 3}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\sqrt{3}}{2}$

In trigonometry:

$sin(60^{\circ}) = \frac{\sqrt{3}}{2}$

Hence:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= sin(60^{\circ})$

3 0

3 years ago

A father's age is three less than two times the son's age. The difference in their ages is 30 years. Find the son's age.

kkurt [141]

You can set up a systems of equations to solve this problem.

The equation y = 2x-3 represents the father's age where y = The father's age and x = The son's age.

The equation 30=y-x represents the difference between the two ages.

In order to be able to solve a system, the two equations can be in the same form. (They don't need to be it's just easier for me to have them in the same form) One is in standard form (ax+by= c) and the other one is in slope intercept form (y=mx+b where m is the slope and b is the y- intercept).

Lets put the equation y=2x-3 into standard form.

y=2x-3

+3 +3

y+3=2x

-y -y

3=2x-y

We have the two equations 30=y-x and 3=2x-y

Now to solve the system.

30=y-x

3=2x-y or 3=-y+2x

30=y-x

3=-y+2x The -y and y cancel each other out since they are the same term but are the inverse of each other one is neg one is pos.

Your left with

30=-x Now you just combine the two equations. 30+3 and 2x-x

3=2x

33=x The son's age is 33. To Find the Fathers age we would just plug 33 for x into one of the equations to find the Fathers age.

SON'S AGE IS 33

6 0

3 years ago