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alexandr402 [8]
2 years ago
14

Frank's paper airplane glided 78.9 m. Sarah's plane glided 85 m. How many more centimeters did Sarah's plane glide? 1 m= 100 cm

Mathematics
1 answer:
Olegator [25]2 years ago
4 0

Answer:

610 cm

Step-by-step explanation:

78.9 x 100 = 7890 cm  85 x 100 = 8,500 cm        

8,500 - 7890 = 610 cm

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The circle above has an area of 144 pi cm^2. What is the area of the blue sector? Use 3.14 for pi.
sineoko [7]

Answer:

150.72 cm^2

Step-by-step explanation:

The blue area has an angle of 120 degrees, and 120/360 = 1/3, which shows that the blue area is 1/3 of the circle. In that case, the blue area is just 144pi/3. That simplifies to 48 pi.

48*3.14 = 150.72

8 0
3 years ago
HELP IT"S ALGEBRA CAN SOMEONE DO THIS QUICK
Ahat [919]

Answer:

(2,2)

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Perform the indicated operation <br> 5(3x^3)^3-2(3x^3)
Pie
<span>5(3x^3)^3-2(3x^3)
=</span><span>5(3^3 x^9) - 6x^3
= 135x^9 - 6x^3
= 3x^3 (45x^6 - 2)</span>
5 0
3 years ago
james and bethany morrison are celebrating their 10th anniversary by having a reception at a local reception hall. they have bud
saveliy_v [14]

Answer:

They can invite 136 while staying in budget

Step-by-step explanation:

Firstly, you know they will have to pay an $80 cleaning fee, therefore, you can subtract 80 from 5,000:

5,000-80 = 4,920

After doing this, you can take 4,920 and divide it by 36 (the price per person).

4,920/36 = 136.67

Because you can not have .67 of a person, your closest number you can use is 136.

leaving them with $24

5 0
3 years ago
The heights of a random sample of 50 college students showed a mean of 174.5 centimeters and a standard deviation of 6.9 centime
Minchanka [31]

Answer:

Step-by-step explanation:

Hello!

For me, the first step to any statistics exercise is to determine what is the variable of interest and it's distribution.

In this example the variable is:

X: height of a college student. (cm)

There is no information about the variable distribution. To estimate the population mean you need a variable with at least a normal distribution since the mean is a parameter of it.

The option you have is to apply the Central Limit Theorem.

The central limit theorem states that if you have a population with probability function f(X;μ,δ²) from which a random sample of size n is selected. Then the distribution of the sample mean tends to the normal distribution with mean μ and variance δ²/n when the sample size tends to infinity.

As a rule, a sample of size greater than or equal to 30 is considered sufficient to apply the theorem and use the approximation.

The sample size in this exercise is n=50 so we can apply the theorem and approximate the distribution of the sample mean to normal:

X[bar]~~N(μ;σ2/n)

Thanks to this approximation you can use an approximation of the standard normal to calculate the confidence interval:

98% CI

1 - α: 0.98

⇒α: 0.02

α/2: 0.01

Z_{1-\alpha /2}= Z_{1-0.01}= Z_{0.99} =2.334

X[bar] ± Z_{1-\alpha /2} * \frac{S}{\sqrt{n} }

174.5 ± 2.334* \frac{6.9}{\sqrt{50} }

[172.22; 176.78]

With a confidence level of 98%, you'd expect that the true average height of college students will be contained in the interval [172.22; 176.78].

I hope it helps!

4 0
3 years ago
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