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AlexFokin [52]
4 years ago
15

Cube-shaped blocks are packed into a cube-shaped storage container. The edge of the storage container is 2 1/2 feet. The edge le

ngth of each block is 1/5 the edge length of the storage container. What is the volume, in cubic feet, of one cube-shaped block?
Mathematics
1 answer:
GarryVolchara [31]4 years ago
4 0

Answer:

Volume of one cube shaped block is, 0.125 cubic feet

Step-by-step explanation:

Volume of a cube(V) is given by:

V = a^3                 .....[1]

where a is the edge length of the cube.

As per the statement:

Cube-shaped blocks are packed into a cube-shaped storage container. The edge of the storage container is 2 1/2 feet.

⇒\text{Edge length of storage} = 2\frac{1}{2} = 2.5 ft

It is also given that:

The edge length of each block is 1/5 the edge length of the storage container

⇒\text{Edge length of each block (a)} = \frac{1}{5} \cdot 2.5 = 0.5 ft

Substitute this in [1] we have;

V = (0.5)^3 = 0.125 ft^3

Therefore,  volume, in cubic feet, of one cube-shaped block is, 0.125

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Lera25 [3.4K]

The solution can be simplified to determine when the object will hit the ground is; h(t) = -9.8t² + 20t + 60

<h3>What is projectile motion?</h3>

Projectile motion is the motion of an object thrown or projected into the air, subject to only the acceleration of gravity. The object is called a projectile, and its path is called its trajectory

Projectile motion

We are told that the projectile motion of an object can be modeled using;

h(t) = gt² + v0*t + h0

Where;

g is the acceleration due to gravity

t is the time since launch

h(t) is the height of the projectile after time t

v0 is the initial velocity

h0 is the initial height.

Now, we are given;

The acceleration due to gravity; g = –9.8 m/s²

Initial velocity; v0 = 20 m/s

Initial height; h0 = 60 m

Hence solution can be simplified to determine when the object will hit the ground is; h(t) = -9.8t² + 20t + 60 h(t) = -9.8t² + 20t + 60

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3 0
2 years ago
1. The perpendicular bisector of side AB of ∆ABC intersects side AB at point D and BC at point E. If m∠CAB = 82° and m∠C = 68°,
olga2289 [7]
<h3>Answer:</h3>
  • ∠CAE = 52°
  • ∠ACB = 110°
<h3>Explanation:</h3>

A drawing can help.

1. The sum of angles of ΔABC is 180°, so ∠B is ...

... ∠B = 180° - ∠A - ∠C = 180° -82° -68° = 30°

ΔABE is isosceles, so ∠EAB = ∠B = 30°.

The sum of angles CAE and EAB will be the measure of ∠A, so we have ...

... ∠CAE + ∠EAB = ∠A

... ∠CAE + 30° = 82° . . . fill in the known values

... ∠CAE = 52° . . . . . . . . subtract 30°

2. ∠CPQ is an external angle to the internal angle CPA of ΔCPA. Thus it is the sum of angles PAC and PCA. Since ΔCPA is isosceles, ∠PAC = ∠PCA and each is half of their sum. That is

... ∠PCA = ∠CPQ/2 = 39°

Likewise, ∠CPQ is an external angle to ΔCQB so is the sum of the equal angles QBC and QCB. Then ...

... ∠QCB = ∠CQP/2 = 31°

The sum of angles in ΔCPQ is 180°, so we have ...

... ∠CPQ + ∠CQP + ∠PCQ = 180°

... 78° + 62° + ∠PCQ = 180° . . . fill in the given values

... ∠PCQ = 40° . . . . . . . . . . . . . .subtract 140°

The angle of interest is the sum of ∠ACP, ∠PCQ, and ∠QCB, so is ...

... ∠ACB = 39° + 40° + 31°

... ∠ACB = 110°

7 0
3 years ago
B-13=7 как решить этот уровнения​
beks73 [17]

Answer:

b equals 20

Step-by-step explanation:

b - 13 = 7

7 + 13 = b

7 + 13 = 20

7 0
3 years ago
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