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Svetllana [295]
3 years ago
10

Tamara wants to find the distance from (2, –10) to other points. For which points in the same quadrant as (2, –10) could Tamara

use a number line to find the distance? Check all that apply. (2, –2) (10, –10) (3, –2) (2, –9) (7, –10) (9, –2) (10, –2) (12, –1)
Mathematics
2 answers:
Hunter-Best [27]3 years ago
7 0

Answer:

The points for which Tamara could use a number line to find their distance from (2, -10) are;

(10, -10), (7, -10) and (2, -2)

Step-by-step explanation:

A number line is a straight line having equal divisions which are numbered

The two points for which Tamara can use a number line to find the distance between the points are points that have the same y-coordinate values including (10, -10) and (7, -10) which are points that lie on the same horizontal line parallel to the x-axis

The distance between the above points and (2, -10) are;

10 - 2 = 8 units and 7 - 2 = 5 units

Similarly Tamara can use a number line to find the distance between the points (2, -10) and (2, -2) as follows;

The distance between (2, -10) and (2, -2) is -10 - (-2) = -8 units

Therefore, the points Tamara could use a number line to find the distance are;

(10, -10), (7, -10) and (2, -2).

cricket20 [7]3 years ago
3 0

Answer:

A, B, D, E

Step-by-step explanation:

its these answers if ur too lazy to read

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When two lines intersect at 90° degrees angle, the lines are perpendicular to each other. Two perpendicular lines, their slope will give a product of -1

i.e. if the first's line slope is 5, then the second line's will be -1 ÷ 5 = -¹/₅

To find the slope of a line, we divide the vertical distance by the horizontal distance. 

We'll use the trial and error method to find the right pairing

Let's start with A(3, 3) and B(12, 6)

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Try C(16, -6); check the slope with B(12, 6)

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Let's do A(-10, 5) and B(12, 16)

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--------------------------------------------------------------------------------------------------------------

Let's try A(12, -14) and B(-16, 21)

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Horizontal distance = -16 - 12 = -28

The slope AB = ³⁵/-₂₈ = ⁵/₋₄

We need the perpendicular slope to be -1 ÷ -⁵/₄ = ⁴/₅

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Tile 7 matches tile 8

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Take A(-12, -19) and B(20, 45)

Vertical distance = 45 - -19 = 64

Horizontal distance = 20 - -12 = 32

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Vertical distance = 45 - 52 = -7

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The slope is ⁻⁷/₁₄ = -¹/₂

Tile 9 pairs with tile 2

-----------------------------------------------------------------------------------------------------------

Conclusion

Tile 1 ⇒ Tile 4

Tile 3 ⇒ Tile 6

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Tile 9 ⇒ Tile 2

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