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Alja [10]
3 years ago
12

PLEASE HELP VERY URGENT!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics
2 answers:
diamong [38]3 years ago
7 0

Q1.  Look at the picture.

C.\\y=-\dfrac{1}{3}x+3\\\\y=2x-4

Q2. Look at the picture.

A.\ 4-t

Q3.

Put the value of x = 2 to the equation 3x + y = 5:

3(2)+y=5

6+y=5       <em>subtract 6 from both sides</em>

y=-1\\\\F.\ -1

Q4.

\left\{\begin{array}{ccc}n=3m-11&(*)\\2m+3n=0&(**)\end{array}\right

Substitute (*) to (**):

2m+3(3m-11)=0            <em>use distributive property</em>

2m+(3)(3m)+(3)(-11)=0

2m+9m-33=0       <em>add 33 to both sides</em>

11m=33      <em>divide both sides by 11</em>

m=3

Put the value of m to (*):

n=3(3)-11\\\\n=9-11\\\\n=-2

C. (3,\ -2)

Q5.

w - width

3w - length

24 in - the sum of length and width

The equation:

w+3w=24

4w=24           <em>divide both sides by 4</em>

w=6\ in

3w=3(6)=18\ in

J.\ 18\ inches


natita [175]3 years ago
7 0

Answer:

j. 18 inches

Step-by-step explanation:

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Can someone please help me?
Vladimir79 [104]

Answer:

<h3> ( - 1 , - 1 )</h3>

Option D is the correct option.

Step-by-step explanation:

y = - 2x - 3 → Equation ( i )

y = 3x + 2 → Equation ( ii )

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y + 2x = - 3

y - 3x = 2

---------------------

5x = - 5

Divide both sides of the equation by 5

\frac{5x}{5}  =  \frac{ - 5}{5}

Calculate

x =  - 1

Again, Putting the value of x in equation ( ii ) in order t get the value of y

y = 3x + 2

plug the value of x

= 3  \times ( - 1) + 2

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=  - 3 + 2

Calculate

=  - 1

Therefore, The possible solution of the system is the ordered pair ( x , y )

(x \:, y \: ) =  ( - 1 \:, - 1)

-----------------------------------------------------------------------

Check if the given ordered pair is the solution of the system of equation

- 1 =  - 2 \times ( - 1)  - 3

- 1 = 3 \times ( - 1) + 2

Simplify the equation

- 1 =  - 1

- 1 =  - 1

Since all the equalities are true, the ordered pair is the solution of the system.

<h3>( x , y ) = ( - 1 , - 1 )</h3>

Hope this helps..

Best regards!!

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The denominator would be 6.


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