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3 years ago

It takes 3 minutes to walk 37.5 meters. What is the speed

Mathematics

2 answers:

BlackZzzverrR [31]3 years ago

6 0

The answer is 12.5 meters per seconds

Rashid [163]3 years ago

5 0

Answer:

It's 12.5 meters per minute

Step-by-step explanation:

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Answer:

D) The expression 9 - p has exactly 2 terms

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3 years ago

Hi, please help me :)

bearhunter [10]

Answer:

D. Linear

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3 years ago

2/5, 1/8 common denominator <br> 3/4, 1/2 common denominator <br> 2/3, 1/6 common denominator

aniked [119]

1st one is 40
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3 years ago

Integrate this two questions

tankabanditka [31]

Simplify the integrands by polynomial division.

$\dfrac{t^2}{1 - 3t} = -\dfrac19 \left(3t + 1 - \dfrac1{1 - 3t}\right)$

$\dfrac t{1 + 4t} = \dfrac14 \left(1 - \dfrac1{1 + 4t}\right)$

Now computing the integrals is trivial.

$\displaystyle \int \frac{t^2}{1 - 3t} \, dt = -\frac19 \int \left(3t + 1 - \frac1{1-3t}\right) \, dt \\\\ = -\frac19 \left(\frac32 t^2 + t + \frac13 \ln|1 - 3t|\right) + C \\\\ = \boxed{-\frac{t^2}6 - \frac t9 - \frac{\ln|1-3t|}{27} + C}$

where we use the power rule,

$\displaystyle \int x^n \, dx = \frac{x^{n+1}}{n+1} + C ~~~~ (n\neq-1)$

and a substitution to integrate the last term,

$\displaystyle \int \frac{dt}{1-3t} = -\frac13 \int \frac{du}u \\\\ = -\frac13 \ln|u| + C \\\\ = -\frac13 \ln|1-3t| + C ~~~ (u=1-3t \text{ and } du = -3\,dt)$

$\displaystyle \int \frac t{1+4t} \, dt = \frac14 \int \left(1 - \frac1{1+4t}\right) \, dt \\\\ = \frac14 \left(t - \frac14 \ln|1 + 4t|\right) + C \\\\ = \boxed{\frac t4 - \frac{\ln|1+4t|}{16} + C}$

using the same approach as above.

5 0

2 years ago

If m∠XWY = 20, m∠XWZ = 40, and XY = 16, what is the value of YZ? Three rays extend out from W through X, Y, and Z. Segments are

Korvikt [17]

Answer:

YZ=16

Explanation:

XWY=20 XWZ=40, XWY is half of XWZ, which means ZWY =20. Now you can say that the triangles are congruent through the AAS postulate, so you know that YZ-16 because of CPCTC

5 0

3 years ago