<span>ill try to help get u started
y = x^2 +1 ;
</span>The y values are 10,5,2,1,2,5,10
For y = x^2-1, they are
<span>8,3,0,-1,0,3,8</span>
Answer:
y = x +1
Step-by-step explanation:
y= mx + b
where m is the slope and b is the y-intercept
m = (y2-y1)/ (x2-x1) = 2+4 / 3+3 = 6/6 = 1
from the point -slope equation we have
y-y1 = m* (x-x1)
y-3 = 1* ( x-2)
y= x -2+3
y= x +1
so the slope m=1 and the y-intercept b=1
note that gradient = 
at x = a
calculate for each pair of functions and compare gradient
(a)
= 2x and = - 1
at x = 4 : gradient = 8 and - 1 : 8 > - 1
(b)
= 2x + 3 and = - 2
at x = 2 : gradient = 7 and - 2 and 7 > - 2
(c)
= 4x + 13 and = 2
at x = - 7 : gradient = - 15 and 2 and 2 > - 15
(d)
= 6x - 5 and = 2x - 2
at x = - 1 : gradient = - 11 and - 4 and - 4 > - 11
(e)
y = √x = 
= 1/(2√x) and = 2
at x = 9 : gradient = 
and 2 and 2 >
Answer:
tangent (angle) or tan (angle)
Step-by-step explanation:
tangent (angle) = the leg opposite the angle / the leg adjacent to the angle
Answer:
x =1/12(1-√(97) )
Step-by-step explanation:
