The 3rd selection is appropriate.
.. 5b +1 = a = 3b +5
by the transitive property of equality,
.. 5b +1 = 3b +5
10x^3 is the greatest common factor
Answer:
SQUARE
Step-by-step explanation:
If Quadrilateral MNPQ has vertices M(4,0), N(0,6), P(-4,0) and Q(0, -6).
Find the following MN, NP, PQ and MQ
Using the formula for calculating the distance between two points
MN = √(6-0)²+(0-4)²
MN = √6²+4²
MN = √36+16
MN = √52
MN = 2√13
NP = √(0-6)²+(-4-0)²
NP = √6²+4²
NP = √36+16
NP = √52
NP = 2√13
PQ = √(-6-0)²+(0-(-4))²
PQ = √6²+4²
PQ = √36+16
PQ = √52
PQ = 2√13
MQ = √(-6-0)²+(0-4)²
MQ = √6²+4²
MQ = √36+16
MQ= √52
MQ = 2√13
Since the length of all the sides are equal, hence the shape is a SQUARE
Answer:
a 1/3 5/3 is right i just did this
Step-by-step explanation:
<h3>
Answer: Choice B 
</h3>
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Work Shown:
Angle theta is between 0 and pi/2, so this angle is in quadrant Q1.
Square both sides of the given equation
Then use the pythagorean trig identity to get
