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neonofarm [45]
3 years ago
6

X - 0.25x = 0.75x

Mathematics
1 answer:
MrRissso [65]3 years ago
3 0
I have no idea myself
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Jackson played a video game for 1/6 hour. Bailey played a video game for 1/3 hour. Who played the video game for greater amount
Oksana_A [137]

Answer:

Bailey played longer.

Step-by-step explanation:

1/3 of an hour would be 20 minutes. 1/6 of an hour is 10 minutes.

6 0
4 years ago
The scores on the GMAT entrance exam at an MBA program in the Central Valley of California are normally distributed with a mean
Kaylis [27]

Answer:

58.32% probability that a randomly selected application will report a GMAT score of less than 600

93.51%  probability that a sample of 50 randomly selected applications will report an average GMAT score of less than 600

98.38% probability that a sample of 100 randomly selected applications will report an average GMAT score of less than 600

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 591, \sigma = 42

What is the probability that a randomly selected application will report a GMAT score of less than 600?

This is the pvalue of Z when X = 600. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{600 - 591}{42}

Z = 0.21

Z = 0.21 has a pvalue of 0.5832

58.32% probability that a randomly selected application will report a GMAT score of less than 600

What is the probability that a sample of 50 randomly selected applications will report an average GMAT score of less than 600?

Now we have n = 50, s = \frac{42}{\sqrt{50}} = 5.94

This is the pvalue of Z when X = 600. So

Z = \frac{X - \mu}{s}

Z = \frac{600 - 591}{5.94}

Z = 1.515

Z = 1.515 has a pvalue of 0.9351

93.51%  probability that a sample of 50 randomly selected applications will report an average GMAT score of less than 600

What is the probability that a sample of 100 randomly selected applications will report an average GMAT score of less than 600?

Now we have n = 50, s = \frac{42}{\sqrt{100}} = 4.2

Z = \frac{X - \mu}{s}

Z = \frac{600 - 591}{4.2}

Z = 2.14

Z = 2.14 has a pvalue of 0.9838

98.38% probability that a sample of 100 randomly selected applications will report an average GMAT score of less than 600

8 0
3 years ago
Plz help with this question fast
Sedaia [141]

Answer:

The answer is C; y=x+2

Step-by-step explanation:

y=mx+b (3, 5)

5=1(3)+b

5=3+b

subtract 3 from both sides of the equation

2=b

equation; y=mx+b

                y=x+2

8 0
3 years ago
Read 2 more answers
What is 7 over 9 subtract 1 over 3
Firlakuza [10]
The answer is 4/9 or 0.44444
5 0
4 years ago
Read 2 more answers
PLEASE ANWSER CORRECTLY!! I WILL MARK BRAINIEST!!!
tankabanditka [31]

Answer:

x = 10°

z = 66°

Step-by-step explanation:

(9x - 24)° + (12x - 6)°  = 180°\\21x° - 30° = 180° \\ 21 x° = 180°  +  30° \\ 21x° = 210° \\ x° =  \frac{180°}{30°}  \\ x° = 10°

z° = 9x - 24 ( vertically opposite )

z° = 9(10) - 24

z° = 90 - 24

z° = 66°

<h3>Hope it is helpful.....</h3>
3 0
3 years ago
Read 2 more answers
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