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elixir [45]
3 years ago
10

GCF of 110x^3, 30x^4, 60x^8

Mathematics
1 answer:
liberstina [14]3 years ago
8 0
10x^3 is the greatest common factor
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A circle has a radius of 6. An arc in this circle has a central angle of 330
sashaice [31]

Answer: Arc\ lenght\approx34.55\ units

Step-by-step explanation:

<h3> The complete exercise is: " A circle has a radius of 6. An arc in this circle has a central angle of 330 degrees. What is the arc length?"</h3><h3></h3>

To solve this exercise you need to use the following formula to find the Arc lenght:

Arc\ lenght=2\pi r(\frac{C}{360})

Where "C" is the central angle of the arc (in degrees) and "r" is the radius.

In this case, after analize the information given in the exercise, you can identify that the radius and the central angle in degrees, are:

r=6\ units\\\\C=330

Therefore, knowing these values, you can substitute them into the formula:

Arc\ lenght=2\pi (6\ units)(\frac{330}{360})

And finally,you must evaluate in order to find the Arc lenght.

You get that this is:

Arc\ lenght=2\pi (6\ units)(\frac{11}{12})\\\\Arc\ lenght=11\pi \ units\\\\Arc\ lenght\approx34.55\ units

3 0
3 years ago
Read 2 more answers
2
antiseptic1488 [7]

Answer: 123

Step-by-step explanation: Stop cheating idiot

5 0
3 years ago
Solve the inequality k - 3 &lt; 5
k0ka [10]

k-3+3<5+3 is the explanation and the answer is k<8

7 0
2 years ago
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Circle C has radius of 10 cm. Each of points B and D is on the midpoint of the radius. Find the area of the shaded region.
olya-2409 [2.1K]
Simple :)
Area of shaded part = are of 1/4 circle - area of both triangles.
Are of circle = pie r^2 so 100x3.14 = 314 cm2.
Area of triangle AOB= area of triangleDOE = bh/2= 5x10/2= 25 each
However, the traingles share a common area which is quad DOB(I)
Lets take traingle AOE, whose are is bh/2=10x10/2=50cm2.
50-area of triangle A(I)E= 50-(
7 0
3 years ago
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∣x∣=−5<br> find an absoulute value
kati45 [8]

Answer:

5

Step-by-step explanatio

8 0
3 years ago
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