Answer:

Step-by-step explanation:
GIVEN: A bag contain
red marbles,
green marbles and
blue marble. A marble is chosen at random from the bag and not replaced, then a second marble is chose.
TO FIND: What is the probability both marbles are green.
SOLUTION:
Total marbles in bag 
total number of green marbles 
Probability that first marble will be green 

Probability that second marble will be green 

As both events are disjoint
probability both marbles are green 

Hence the probability both marbles are green is 
I believe this should be right
Im not smart im not that sure of my answer but 23.3
Using an exponential function, it is found that it takes 5.42 years for the car to halve in value.
<h3>What is an exponential function?</h3>
A decaying exponential function is modeled by:

In which:
- A(0) is the initial value.
- r is the decay rate, as a decimal.
In this problem, the car depreciates 12% a year in value, hence r = 0.12 and the equation is given by:
.
It halves in value at t years, for which A(t) = 0.5A(0), hence:






t = 5.42.
It takes 5.42 years for the car to halve in value.
More can be learned about exponential functions at brainly.com/question/25537936
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Answer:
Is it bad that I'm a senior and have no idea how to do this?
Step-by-step explanation: