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Marina86 [1]
3 years ago
9

The perimeter of ABCD is 26 cm The area of PQRS is 45 cm(squares)Find the length of AB

Mathematics
2 answers:
Oksanka [162]3 years ago
7 0
Area of rectangle= LxW
45cm2 divided by 10cm = 4.5cm
B-C= 4.5cm
Perimeter of rectangle= L+W x2
26/2 =13cm -4.5= 8.5cm
sammy [17]3 years ago
4 0
QR = 10cm and the area of that rectangle is 45cmsq so to work out PQ you do 45/10 = 4.5cm
PQ= 4.5cm

As BC = PQ they both equal 4.5cm

and the perimeter of ABCD is 26cm you so 26- (4.5x2) = 17
and 17/2 = 8.5cm

AB is 8.5cm
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3 years ago
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Step-by-step explanation:

multiple 6 by 12 to get the area of the individual plot of land given to a single worker.

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4 years ago
Use the Taylor series you just found for sinc(x) to find the Taylor series for f(x) = (integral from 0 to x) of sinc(t)dt based
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In this question (brainly.com/question/12792658) I derived the Taylor series for \mathrm{sinc}\,x about x=0:

\mathrm{sinc}\,x=\displaystyle\sum_{n=0}^\infty\frac{(-1)^nx^{2n}}{(2n+1)!}

Then the Taylor series for

f(x)=\displaystyle\int_0^x\mathrm{sinc}\,t\,\mathrm dt

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f(x)=\displaystyle\int\sum_{n=0}^\infty\frac{(-1)^nx^{2n}}{(2n+1)!}\,\mathrm dx=C+\sum_{n=0}^\infty\frac{(-1)^nx^{2n+1}}{(2n+1)^2(2n)!}

We have f(0)=0, so C=0 and so

f(x)=\displaystyle\sum_{n=0}^\infty\frac{(-1)^nx^{2n+1}}{(2n+1)^2(2n)!}

which converges by the ratio test if the following limit is less than 1:

\displaystyle\lim_{n\to\infty}\left|\frac{\frac{(-1)^{n+1}x^{2n+3}}{(2n+3)^2(2n+2)!}}{\frac{(-1)^nx^{2n+1}}{(2n+1)^2(2n)!}}\right|=|x^2|\lim_{n\to\infty}\frac{(2n+1)^2(2n)!}{(2n+3)^2(2n+2)!}

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7 0
3 years ago
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dalvyx [7]

Answer:

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Hope this helps! :)

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