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Sergio039 [100]
2 years ago
9

PLEASE HELP!!!!!!! will mark brainliest!!!!

Mathematics
1 answer:
Setler [38]2 years ago
4 0
15.25. hope this helps
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Help me out, please!
VMariaS [17]

Answer:

y = 2/3(x - 3)

Step-by-step explanation:

slope of the line is 2/3

we can use point (3,0)

formula: y - y = m(x - x)

y - 0 = 2/3 (x - 3)

y = 2/3(x - 3)

5 0
2 years ago
An electrical shop reduces display goods by 20%. A display TV is sold for £200. What is the usual price of the same TV?
Fynjy0 [20]
200 is 80%
200 / 80 = 2.50 (1%)
2.50 * 100 = £250

Hope this helps.
8 0
2 years ago
If a basketball has a volume of 12,114.7 cm3, what is the distance across of a basketball
kirza4 [7]


All we need to do is start with the volume formula. Then, input the volume and solve the equation for the radius. And double it to get the diameter.

V = (4/3)pi(r^3)
12114.7 = (4/3)pi(r^3)  Divide both sides by (4/3) and pi
2893.64 = r^3              Take the cube root of both sides
14.25 = r

So the diameter is about 28.5 cm (14.25 x 2 = 28.5)
4 0
2 years ago
Whats the variable for -11b+7+=40
solniwko [45]

Answer:

-3

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
4(3x^2y^4)^3 / (2x^3y^5)^4
tatyana61 [14]

Solving the expressions  \frac{4(3x^2y^4)^3}{(2x^3y^5)^4} we get \frac{27}{4x^{6}y^{8}}

Step-by-step explanation:

We need to Solve the expression: \frac{4(3x^2y^4)^3}{(2x^3y^5)^4}

Solving:

\frac{4(3x^2y^4)^3}{(2x^3y^5)^4}

=\frac{4(3^3x^6y^{12})}{(2^4x^{12}y^{20})}\\=\frac{4(27x^6y^{12})}{(16x^{12}y^{20})}\\=\frac{108x^6y^{12}}{16x^{12}y^{20}}

Applying exponent rule: \frac{x^a}{x^b}=x^{a-b}

=\frac{108x^{6-12}y^{12-20}}{16}\\=\frac{27x^{-6}y^{-8}}{4}

Another exponent rule says: x^{-a}=\frac{1}{x^a}=

=\frac{27}{4x^{6}y^{8}}

So, solving the expressions  \frac{4(3x^2y^4)^3}{(2x^3y^5)^4} we get \frac{27}{4x^{6}y^{8}}

Keywords: Solving Exponents  

Learn more about Solving Exponents at:

  • brainly.com/question/13174260
  • brainly.com/question/13174254
  • brainly.com/question/13174259

#learnwithBrainly

8 0
3 years ago
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