All categories

3 years ago

PLEASE HELP ASSP !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!111

Mathematics

2 answers:

PilotLPTM [1.2K]3 years ago

6 0

Expand the brackets
5t+15=-3.5
move values to the other side
5t=11.5
t=2.3

natka813 [3]3 years ago

4 0

Answer:

2.3

Step-by-step explanation:

Your beginning equation is 5 (t + 3) = -3.5. You start by dividing by 5. This leaves you with t + 3 = 0.7. If you add 3 you get 2.3

You might be interested in

100 POINT QUESTION!!!!!!!!!!!!!!!!!!!!!!!!!

ehidna [41]

Answer: D is my best guess

Step-by-step explanation:

6 0

3 years ago

Solve the proportion. i need help.<br> x+3/6=8/3<br><br> x=?

stellarik [79]

Answer:

x = 2 1/6 (13/6)

Step-by-step explanation:

to solve the proportion you must first find the LCF or least common factor

that is 6

so turn 8/3 into 16/6 by multiplying it by 2/2

x + 3/6 = 16/6

then you subtract 3/6 from both sides

x = 13/6

x is 2 1/6

6 0

2 years ago

Read 2 more answers

Dave rents a limousine for his wife's birthday. The hourly rate is $80. They used the limo for 5 hours, plus Dave gave te=he dri

Dahasolnce [82]

Answer:

$480

Step-by-step explanation:

So first, you find how much he paid per hour which would be 80 * 5 = $400. Then, you have to add the tip in so you do $400 * 1.2 (or 120%) = $480.

6 0

3 years ago

If the distance from A (5,6) to B (1, b) is twice the distance from B to

Nimfa-mama [501]

Answer:

The possible values of $b$ are -2.944 and -9.055, respectively.

Step-by-step explanation:

From statement we know that $AB = 2\cdot BC$ . By Analytical Geometry, we use the equation of a line segment, which is an application of the Pythagorean Theorem:

$AB = 2\cdot BC$

$\sqrt{(x_{B}-x_{A})^{2}+(y_{B}-y_{A})^{2}} = 2\cdot \sqrt{(x_{C}-x_{B})^{2}+(y_{C}-y_{B})^{2}}$ (1)

Where:

$x_{A}$ , $x_{B}$ , $x_{C}$ - x-Coordinates of points A, B and C.

$y_{A}, y_{B}, y_{C}$ - y-Coordinates of points A, B and C.

$(x_{B}-x_{A})^{2}+(y_{B}-y_{A})^{2} = 4\cdot (x_{C}-x_{B})^{2}+4\cdot (y_{C}-y_{B})^{2}$

Then, we expand and simplify the expression above:

$x_{B}^{2}-2\cdot x_{A}\cdot x_{B} +x_{A}^{2} +y_{B}^{2}-2\cdot y_{A}\cdot y_{B} + y_{A}^{2} = 4\cdot (x_{C}^{2}-2\cdot x_{C}\cdot x_{B}+x_{B}^{2})+4\cdot (y_{C}^{2}-2\cdot y_{C}\cdot y_{B}+y_{B}^{2})$

$x_{B}^{2}-2\cdot x_{A}\cdot x_{B} + x_{A}^{2} +y_{B}^{2}-2\cdot y_{A}\cdot y_{B} + y_{A}^{2} = 4\cdot x_{A}^{2}-8\cdot x_{C}\cdot x_{B}+4\cdot x_{B}^{2}+4\cdot y_{C}^{2}-8\cdot y_{C}\cdot y_{B}+4\cdot y_{B}^{2}$

If we know that $x_{A} = 5$ , $y_{A} = 6$ , $x_{B} = 1$ , $y_{B} = b$ , $x_{C} = 1$ and $y_{C} = -3$ , then we have the following expression:

$1 -10 +25 +b^{2} -12\cdot b+36 = 100 -8 +4 +36+24\cdot b +4\cdot b^{2}$

$b^{2}-12\cdot b +52 = 4\cdot b^{2}+24\cdot b +132$

$3\cdot b^{2}+36\cdot b +80 = 0$

This is a second order polynomial, which means the existence of two possible real solutions. By Quadratic Formula, we have the following y-coordinates for point B:

$b_{1} \approx -2.944$ , $b_{2} \approx -9.055$