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tino4ka555 [31]
3 years ago
13

A pleasure filled Excursion into the realm of Physics: 1. Before applying the Super Teflon Anti-friction spray Clark Griswold re

views the trial run stats. His 85.0 kg mass took 5.00 sec to stop with an applied force of 15.0 N. The titanium disc sled had a mass of 5.20 kg. What is Clark's velocity before the stopping force is applied?​
Physics
1 answer:
damaskus [11]3 years ago
7 0

Answer:

/

Explanation:

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Answer: Option (b) is the correct answer.

Explanation:

Kinetic energy is the energy of an object or particle when it is in motion.

Mathematically,   Kinetic energy = \frac{1}{2}mass \times (velocity)^{2}

It is given that toy truck has mass = 0.75 kg, and velocity = 4 m/s.

Calculate the kinetic energy as follows.

           Kinetic energy = \frac{1}{2}mass \times (velocity)^{2}

                                    = \frac{1}{2}0.75 kg \times (4 m/s)^{2}

                                     = \frac{1}{2}0.75 kg \times 16 m^{2}/s^{2}

                                     = 0.75 kg \times 8 m^{2}/s^{2}

                                     =  6 kg m^{2}/s^{2}

or,       Kinetic energy = 6 joules

Thus, we can conclude that kinetic energy of toy truck is 6 J.


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