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Rudik [331]
3 years ago
5

A student measured the volume of three rocks. The diagram above shows the

Physics
1 answer:
victus00 [196]3 years ago
4 0

Answer:

option B is right

...............

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What is the relationship between the center of gravity and the support base for an object that is in stable equilibrium?
Norma-Jean [14]

Answer:

when the center of gravity is within the washing area, the torque returns in the body to its initial position and is in a stable equilibrium

Explanation:

The concept of center of gravity is equivalent to the concept of center of mass, in this place all external forces applied can be considered.

When we analyze the balance of a body that is the torque it is the one that defines the balance

      τ = F xd

If the torque tends to restore the body to the initial position the balance is stable, but if the torque has to increase the body's rotation the balance is unstable

. When the body tends to rotate the torque with respect to the pivot point at the base it decreases because the distance from the center of gravity to the end of the base decreases in value, but it has to return it to the initial position, the balance is stable. The critical point of this process is when the center of gravity is at the limit of the body base area in this case the torque is zero; If the body rotates a little more the center of gravity is outside the base, the torque changes sign and has to increase the turn, going to an unstable balance.

In summary, when the center of gravity is within the washing area, the torque returns in the body to its initial position and is in a stable equilibrium.

8 0
3 years ago
How much heat is required to raise 100 grams of water (c= 4.18) by 5 degrees Celsius?
Andrei [34K]

Answer:

Heat capacity, Q = 2090 Joules.

Explanation:

Given the following data;

Mass = 100 grams

Specific heat capacity = 4.18 J/g°C.

Temperature = 5°C

To find the quantity of heat required;

Heat capacity is given by the formula;

Q = mct

Where;

Q represents the heat capacity or quantity of heat.

m represents the mass of an object.

c represents the specific heat capacity of water.

t represents the temperature of an object.

Substituting into the formula, we have;

Q = 100*4.18*5

Heat capacity, Q = 2090 Joules.

7 0
3 years ago
HELP ME ASAP!!!!! A patient in the hospital is undergoing testing. The patient's brain is sending electrical signals to motor ne
AysviL [449]

Answer:

The patient could be going through paralysis, which is when the motor neurons are severed which stops electrical signals from passing into the muscles.  It can be caused by severe trauma to the body or psychological stress.

(I'm not sure if this is the best answer so you might want to double-check online)

3 0
3 years ago
Wind comes from the Sun
zzz [600]

Answer:

I am pretty sure is either C or D hope this helps

3 0
3 years ago
Read 2 more answers
To initiate a nuclear reaction, an experimental nuclear physicist wants to shoot a proton into a 5.50-fm-diameter 12C nucleus. T
Crazy boy [7]

Answer:

The value is  u  =  3.23 *10^{7} \  m/s

Explanation:

From the question we are told that

   The diameter of the nucleus is d =  5.50 \ fm = 5.50 *10^{-15} \  c

   The charge of the proton that makes up the nucleus is  Q_2 = \frac{12}{2}  * 1.60 *10^{-19} =9.6*10^{-19} \ C

    The energy to be impacted is  KE_f  =  2.30 \  MeV  =  2.30 *10^{6} \  eV =   2.30 *10^{6}  *  1.60 *10^{-19} = 3.68*10^{-13} \  J

Generally the radius of the nucleus is mathematically represented as

         r  =  \frac{d}{2}

=>      r  =  \frac{5.50 *10^{-15}}{2}

=>      r  =  2.75 *10^{-15} \  m

Generally from the law energy conservation we have that

     Initial \  total  \  energy \ of the \  proton =  final \  total  \  energy \ of the \  proton

i.e

    T_i  =  T_f

Here

   T_i  =  KE_i + PE_i

Here KE_i is the initial kinetic energy which is mathematically represented as

       KE_I  =  \frac{1}{2}  *  m * u ^2

Here  PE_i is the initial potential energy of the proton and the value is  0 J given that the proton is moving

Also  T_f is mathematically represented as

         T_f  =  KE_f + PE_f

Here  

        PE_f  is the final potential energy which is mathematically represented as

         PE_f  = \frac{k * Q_1 * Q_2}{r}

Here Q_1 is the charge on the proton with a value of Q_1 =  1.60 *10^{-19} \  C

So

        PE_f  = \frac{9*10^{9} *(1.60 *10^{-19} ) * ( 9.6 *10^{-19})}{ 2.75 *10^{-15}}

=>     PE_f  = 5.027 *10^{-13 } \  J

So  

         KE_i + PE_i  =  KE_f + PE_f

=>       \frac{1}{2}  *  m * u ^2 +0  =  3.68*10^{-13} + 5.027 *10^{-13 }

Here m is the mass of the moving proton with value m =  1.67*10^{-27} \  kg

So

       \frac{1}{2}  *  1.67*10^{-27}  * u ^2 +0  =  3.68*10^{-13} + 5.027 *10^{-13 }

=>      u  =  \sqrt{\frac{3.68*10^{-13} + 5.027 *10^{-13 }}{0.5  *  1.67*10^{-27}} }

=>       u  =  3.23 *10^{7} \  m/s

5 0
3 years ago
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