Answer:
3. 3(x+y)(x-y)
4. (y²+4)(y+2)(y-2)
5. 2(3x+1)(x+2)
Step-by-Step:
3. 3(x²-y²) = 3(x+y)(x-y)
4. y⁴-16 = (y²+4)(y²-4)= (y²+4)(y+2)(y-2)
5. 6x²+14x+4 = 2(3x²+7x+2) = 2(3x+1)(x+2)
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(I have verified my answers on an online calculator)
Answer:
0 ≤ t ≤ 5.
Step-by-step explanation:
In the function
,
is the independent variable. The domain of
is the set of all values of
that this function can accept.
In this case,
is defined in a real-life context. Hence, consider the real-life constraints on the two variables. Both time and volume should be non-negative. In other words,
.
.
The first condition is an inequality about
, which is indeed the independent variable.
However, the second condition is about
, the dependent variable of this function. It has to be rewritten as a condition about
.
.
Hence, t ≤ 5.
Combine the two inequalities to obtain the domain:
0 ≤ t ≤ 5.
Answer:
b
Step-by-step explanation:
The answer should be A. If you need work I can show you.