All categories

2 years ago

Write the point-slope form of the equation of the line through the given

Mathematics

1 answer:

Marat540 [252]2 years ago

7 0

Answer:

y+3 = -2(x)

Step-by-step explanation:

The equation of the line that passes through the points

(5,-5) and (-5,-1) is y=-2/5x-3.

You might be interested in

What is the greatest number that has one comma when written with numerals and with number names?

Soloha48 [4]

I believe it would be 999,999

7 0

3 years ago

6 + 2/5b = 12 What does “b” equal?

Elis [28]

Answer:

B = 15

Step-by-step explanation:

Combine multiplied terms into a single fraction

6 + 2b/5 = 12

Subtract 6 from both sides

6 + 2b/5 (-6) = 12 (-6) = 2b/5 = 6

Multiply all terms by the same value to eliminate fraction denominators

2b/5 ( x 5) = 6 (x 5)

Simplify

2b = 30

4 0

3 years ago

Read 2 more answers

Item 3

Karo-lina-s [1.5K]

The solution is x=-4, y=-2

8 0

3 years ago

65 - 14 = 65-5-______

Fed [463]

Answer: 60? to be hostens i have no clue sorry i hope this help...

Step-by-step explanation:

7 0

3 years ago

Trigonometry pile up. Anyone mind helping me out with this one?

S_A_V [24]

$cos34^o=\frac{8}{a};\ cos34^o\approx0.829\\\\\frac{8}{a}=0.829\to a\approx9.65\\\\9.65-2.5+3.6=10.75\\\\cos11^o=\frac{b}{10.75};\ cos11^o\approx0.981\\\\\frac{b}{10.75}=0.981\to b\approx10.55\\\\10.55-2.1+2.9=11.35\\\\c^2+3.8^2=11.35^2\\\\c^2=11.35^2-3.8^2\\\\c\approx10.69$

$10.69-3.2=7.49\\\\tan42^o=\frac{d}{7.49};\ tan42^o\approx0.9\\\\\frac{d}{7.49}=0.9\to d\approx6.74\\\\sin37^o=\frac{6.74}{e};\ sin37^o\approx0.602\\\\\frac{6.74}{e}=0.602\to e\approx11.2\\\\11.2+4.3=15.5\\\\sin53^o=\frac{f}{15.5};\ sin53^o\approx0.8\\\\\frac{f}{15.5}=0.8\to f\approx12.4$

$12.4-2.2=10.2\\\\g^2=10.2^2+1.7^2\to g\approx10.34\\\\cos21^o=\frac{10.34}{h};\ cos21^o\approx0.934\\\\\frac{10.34}{h}=0.934\to h=11.07\\\\11.07+1.7=12.77\\\\sin71^o=\frac{x}{12.77};\ sin71^o\approx0.946\\\\\frac{x}{12.77}=0.946\to x\approx12.1\ (cm)\leftarrow Answer$

4 0

3 years ago