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brilliants [131]
3 years ago
10

Need help with this please

Mathematics
1 answer:
Shtirlitz [24]3 years ago
7 0
The ricipricals are 3/8 and 2/13
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(x+4) (x+7) find product<br>​
nataly862011 [7]

Answer:

x2+11x+28    

Step-by-step explanation:

Thus, (x+7)(x+4) multiplies out to x2+4x+7x+28, which can be simplified to        

                                                     x2+11x+28

6 0
3 years ago
Read 2 more answers
Solve this r/6=5 2/3
myrzilka [38]
First, incorporate the 5 into the 2/3 fraction by multiplying the 5 by the 3 and then adding that quantity by the 2, which now makes the fraction:
17/3
Now set it up with the equation:
r/6 = 17/3
r/6×3 = 17/3×3
r/3 = 17
r/3×3 = 17×3
r = 51
4 0
3 years ago
Read 2 more answers
I DESPERATELY NEED HELP PLZ ANSWER THESE QUESTIONS I AM TIMED AND DON"T HAVE MUCH TIME LEFT
Marina CMI [18]

Answer:

Ok I will help you answer the first one the rest yourself?

Step-by-step explanation:

So the question is

6(r-s+t)

we have to time each number by 6

6r-6s+6t

That's how we can simply so the answer is 6r-6s+t

Same thing goes with the others

Hope it helps 0w0

5 0
3 years ago
What number would you add to the equation below to complete the square?x2 - 11x = 0?
nekit [7.7K]

2x - 11 = 0
2. 2
8 0
4 years ago
Write a recursive rule and an explicit rule for the<br> sequence<br> 3,7,11,15
m_a_m_a [10]

Answer:

The Recursive formula for the sequence is:

aₙ = aₙ₋₁ + d

The Explicit formula for the sequence is:

a_n=4n-1

Step-by-step explanation:

Given the sequence

3,7,11,15

Here:

a₁ = 3

computing the differences of all the adjacent terms

7 - 3 = 4, 11 - 7 = 4, 15 - 11 = 4

The difference between all the adjacent terms is the same and equal to

d = 4

We know that a recursive formula basically defines each term of a sequence using the previous term(s).

The recursive formula of the Arithmetic sequence always involves the first term.

a₁ = 3

We know that, in the Arithmetic sequence, every next term can be obtained by adding the common difference and the preceding term.

so

The recursive formula of the sequence is:

aₙ = aₙ₋₁ + d

substitute n = 2 to find the 2nd term

a₂ = a₂₋₁ + d

a₂ = a₁+ d

substitute a₁ = 3 and d = 4

a₂ = 3 + 4

a₂ = 7

Thus, the recursive formula for the sequence 3,7,11,15 is:

aₙ = aₙ₋₁ + d

<u>An explicit rule for the sequence</u>

Given the sequence

3,7,11,15

We already know that

a₁ = 3

d = 4

An arithmetic sequence has a constant difference 'd' and is defined by  

a_n=a_1+\left(n-1\right)d

substituting a₁ = 3 and d = 4

a_n=4\left(n-1\right)+3

a_n=4n-4+3

a_n=4n-1

Therefore, an explicit rule for the  sequence

a_n=4n-1

6 0
3 years ago
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