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Verizon [17]
2 years ago
11

Kurt opened a savings account and deposited $3,000.00 as principal. The account earns 5%

Mathematics
1 answer:
stiv31 [10]2 years ago
7 0

Answer:

Step-by-step explanation:

P = 3,000

r = 5% = 0.05

t = 9 years

Amount after 9 years is

A = P (1+ r)^t

A = 3,000(1+ 0.05)^9 = 3,000 * 1.05^9 = 4653.984648 ≈ $4,653.98

The balance after 9 years, rounded to the nearest cent is

$4,653 and 98 cents

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A cube has a volume of 125 cubic inches. What is the length of each edge?
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A university researcher wants to estimate the mean number of novels that seniors read during their time in college. An exit surv
lys-0071 [83]

Answer:

Population mean = 7 ± 2.306 × \frac{2.29}{\sqrt{9} }

Step-by-step explanation:

Given - A university researcher wants to estimate the mean number

            of  novels that seniors read during their time in college. An exit

            survey was conducted with a random sample of 9 seniors. The

            sample mean was 7 novels with standard deviation 2.29 novels.

To find - Assuming that all conditions for conducting inference have

              been met, which of the following is a 94.645% confidence

              interval for the population mean number of novels read by

              all seniors?

Proof -

Given that,

Mean ,x⁻ = 7

Standard deviation, s = 2.29

Size, n = 9

Now,

Degrees of freedom = df

                                = n - 1

                                = 9 - 1

                                = 8

⇒Degrees of freedom = 8

Now,

At 94.645% confidence level

α = 1 - 94.645%

   =1 - 0.94645

  =0.05355 ≈ 0.05

⇒α = 0.5

Now,

\frac{\alpha}{2} = \frac{0.05}{2}

  = 0.025

Then,

t_{\frac{\alpha}{2}, df }  = 2.306

∴ we get

Population mean = x⁻ ± t_{\frac{\alpha}{2}, df } ×\frac{s}{\sqrt{n} }

                           = 7 ± 2.306 × \frac{2.29}{\sqrt{9} }

⇒Population mean = 7 ± 2.306 × \frac{2.29}{\sqrt{9} }

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