9514 1404 393
Answer:
A
Step-by-step explanation:
Add p to get the n term by itself, then divide by the coefficient of n.
![m=nx-p\\\\m+p=nx \quad\text{add $p$}\\\\\dfrac{m+p}{x}=n \quad\text{divide by $x$}\\\\ \boxed{n=\dfrac{m+p}{x}}](https://tex.z-dn.net/?f=m%3Dnx-p%5C%5C%5C%5Cm%2Bp%3Dnx%20%5Cquad%5Ctext%7Badd%20%24p%24%7D%5C%5C%5C%5C%5Cdfrac%7Bm%2Bp%7D%7Bx%7D%3Dn%20%5Cquad%5Ctext%7Bdivide%20by%20%24x%24%7D%5C%5C%5C%5C%20%5Cboxed%7Bn%3D%5Cdfrac%7Bm%2Bp%7D%7Bx%7D%7D)
QUESTION:
A battery was charged. When the charging began, it was 23 percent full. After 30 minutes of charging, the battery was 89 percent full. how fast did the battery charge and how long did it take?
Solution :
<u>Given</u>
- Initial amount of charge = 23%
- Amount after charge = 89%
<u>procedu</u><u>re</u>
Let the rate of charging be r .
r = (change in charge level) / (time interval) = (89% - 23%) / (30 min) = 2.2 % per minute
charge = (rate of charging)(time) + (initial charge)
100% = r*t + 23%
100% = (2.2 %/min)t + 23%
Solve for t and get
t = [(100 - 23) / 2.2]
Answer = 35 min
1a+18=7a
18=7a-1a
18=6a
6a=18
a=18/6
a=3
Answer:
(3x - 2) (x+5)
Step-by-step explanation:
3x^2 + 13 - 10
15× - 2 = -30
15+-2 = 13.....substitute 15x - 2x in place of 13x
3x^2+15x-2x-10
Factorise the first two values, thrn the second two
3x (x+5) - 2 (x+5)
Gathering the like terms together you eill be left with the following
(3x - 2) (x+5)
I think it is called the final(e) floor. I'm not exactly sure tho...