Question

Helene invested a total of $1,000 in two simple-interest bank accounts. One account paid 8% annual interest; the other paid 9% annual interest. The total amount of interest she earned after one year was $86. Enter and solve a system of equations to find the amount invested in each account. Enter the interest rates in order as given in the problem. (Hint: Change the interest rates into decimals first.)
at 9%.

Answer 1

Answer: -600 and 1600 were invested into the two accounts.

Step-by-step explanation:

x = amount invested in the first account.

y = amount invested in the second account.

You start off with this equation

$x + y = 1000$

$0.08x + 0.09y=86$

Subtract both sides by y.

$x=1000-y$

Subsitude 1000 - x for x for the second equation.

$0.08(1000-y)+0.09y= 86$

Use the distributive property to solve for y.

$80-0.08y+0.09y=86$

$80-0.01y=86$

$6=-0.01y$

$=-600$

Subsitude -600 for y in the first equation and solve for x.

$x-600=1000$

$x=1600$

-600 and 1600 were invested into the two accounts.