Please can someone help me with these questions photo math won’t work

Mathematics

2 answers:

Rudiy272 years ago

5 0

Answer: B, C, A, B
hope this helps you out .

FinnZ [79.3K]2 years ago

3 0

Answer:

B, C, A, B

Step-by-step explanation:

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Engineers want to design passenger seats in commercial aircraft so that they are wide enough to fit 95 percent of adult men. Ass

zimovet [89]

Answer:

$z=1.64$

And if we solve for a we got

$a=14.4 +1.64*1.1=16.204$

The 95th percentile of the hip breadth of adult men is 16.2 inches.

Step-by-step explanation:

Let X the random variable that represent the hips breadths of a population, and for this case we know the distribution for X is given by:

$X \sim N(14.4,1.1)$

Where $\mu=14.4$ and $\sigma=1.1$

For this part we want to find a value a, such that we satisfy this condition:

$P(X>a)=0.05$ (a)

$P(X$ (b)

We can find a quantile in the normal standard distribution who accumulates 0.95 of the area on the left and 0.05 of the area on the right it's z=1.64

Using this value we can set up the following equation:

$P(X$

$P(z$

And we have:

$z=1.64$

And if we solve for a we got

$a=14.4 +1.64*1.1=16.204$

The 95th percentile of the hip breadth of adult men is 16.2 inches.

8 0

2 years ago

f(x) = 500(1.05)x What was the average rate of change of the value of Sophia's investment from the second year to the fourth yea

hjlf

$\bf slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ f(x_2)}}-{{ f(x_1)}}}{{{ x_2}}-{{ x_1}}}\impliedby 
\begin{array}{llll}
average\ rate\\
of\ change
\end{array}\\\\
-------------------------------\\\\
f(x)=500(1.05)^x \qquad 
\begin{cases}
x_1=2\\
x_2=4
\end{cases}\implies \cfrac{f(4)-f(2)}{4-2}
\\\\\\
\cfrac{[500(1.05)^4]~-~[500(1.05)^2]}{4-2}\implies \cfrac{56.503125}{2}\implies 28.2515625$