Jerry observed 5 head in tosses of his coin. Do you think this was a fair coin?

Mathematics

1 answer:

kiruha [24]2 years ago

6 0

It was 50/50 chances

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Suppose that the travel time from your home to your office is normallydistributed with mean 40 minutes and standard deviation 7

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Answer:

The latest time that you should leave home is 12:08 PM

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 40, \sigma = 7$

If you want tobe 95 percent certain that you will not be late for an office appointment at 1 P.M.,what is the latest time that you should leave home?

How many minutes is the 95th percentile of travel time?

it is X when Z has a pvalue of 0.95. So it is X when Z = 1.645. So

$Z = \frac{X - \mu}{\sigma}$

$1.645 = \frac{X - 40}{7}$